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Paperbacks [#permalink] New post 31 Jul 2009, 07:34
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There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441.000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45.000
(B) 360.000
(C) 364.500
(D) 392.000
(E) 396.900
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Re: Paperbacks [#permalink] New post 31 Jul 2009, 09:24
My answer is C. 364,500

I set Hardback = H and Paperback = 9H
36,000 + 9H + H = 441,000
10H = 405,000
H = 40,500

Plug H into the paperback formula
Paperback = 9(40,500)
Paperback = 364,500

Not sure if that is correct but that is how I went about solving it. Let me know.
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Re: Paperbacks [#permalink] New post 31 Jul 2009, 10:17
you havent considered the hardbacks sold while the paperbacks were also being sold.

the answer is option (5)
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Re: Paperbacks [#permalink] New post 31 Jul 2009, 10:59
travern wrote:
you havent considered the hardbacks sold while the paperbacks were also being sold.

the answer is option (5)


Can you explain? I thought that 9H+H was accounting for this.
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Re: Paperbacks [#permalink] New post 31 Jul 2009, 12:09
[EDIT - REMOVED BY USER]

Last edited by nplaneta on 17 Jun 2012, 16:39, edited 1 time in total.
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Re: Paperbacks [#permalink] New post 01 Aug 2009, 09:44
agree with TStokes
My answer is also C. 364,500
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Re: Paperbacks [#permalink] New post 12 Aug 2009, 03:39
C

(441,000 - 36,000)*(9/10) = 364,500.

Posted from my mobile device Image
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Re: Paperbacks [#permalink] New post 12 Aug 2009, 22:51
since 9 times as much as Hardback 10 = 441.000
9 = 441000*9/10 = 364500

C

/Prabu
Re: Paperbacks   [#permalink] 12 Aug 2009, 22:51
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