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There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441.000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45.000
(B) 360.000
(C) 364.500
(D) 392.000
(E) 396.900
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Intern
Joined: 31 Jul 2009
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My answer is C. 364,500
I set Hardback = H and Paperback = 9H
36,000 + 9H + H = 441,000
10H = 405,000
H = 40,500
Plug H into the paperback formula
Paperback = 9(40,500)
Paperback = 364,500
Not sure if that is correct but that is how I went about solving it. Let me know.
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Intern
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you havent considered the hardbacks sold while the paperbacks were also being sold.
the answer is option (5)
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Intern
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travern wrote: you havent considered the hardbacks sold while the paperbacks were also being sold.
the answer is option (5) Can you explain? I thought that 9H+H was accounting for this.
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Intern
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[EDIT - REMOVED BY USER]
Last edited by nplaneta on 17 Jun 2012, 17:39, edited 1 time in total.
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Manager
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agree with TStokes
My answer is also C. 364,500
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Senior Manager
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C (441,000 - 36,000)*(9/10) = 364,500. Posted from my mobile device 
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Manager
Joined: 09 Aug 2009
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since 9 times as much as Hardback 10 = 441.000
9 = 441000*9/10 = 364500
C
/Prabu
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close
