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Pat bought 5 pounds of apples. How many pounds of pears

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Pat bought 5 pounds of apples. How many pounds of pears [#permalink] New post 30 Oct 2007, 19:25
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Pat bought 5 pounds of apples. How many pounds of pears could he have bought for same amount of money?

(1) 1 pound of pears cost $0.5 more that 1 pound of apples
(2) 1 pound of pears cost 1.5 times as much as 1 pound of apples
[Reveal] Spoiler: OA

Last edited by Bunuel on 27 Feb 2013, 06:13, edited 1 time in total.
Edited the question and added the OA.
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Re: gmatprep DS- apples and pears [#permalink] New post 30 Oct 2007, 19:41
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trivikram wrote:
r019h wrote:
Pat bought 5 pounds of apples. How many pounds of pears could he have bought for same amount of money?
1) 1 pound of pears cost $0.5 more that 1 pound of apples
2) 1 pound of pears cost 1.5 times as much as 1 pound of apples


B should be it


st. 1
cost of 1 pound of apples= $x
cost of 1 pound pears= $x+0.5
5 pounds of apples for $5x
and 5x/x+0.5 pounds of pears for $5x INSUFF

st. 2
1 pound of pears= $1.5x
so 5x/1.5x pounds of pears for $5x= 5/1.5 approx= 3 pounds of pears
SUFF
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Re: Pat bought 5 pounds of apples. How many pounds of pears [#permalink] New post 27 Feb 2013, 03:05
I didn't understand statement 2
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Re: Pat bought 5 pounds of apples. How many pounds of pears [#permalink] New post 27 Feb 2013, 06:44
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fozzzy wrote:
I didn't understand statement 2


Pat bought 5 pounds of apples. How many pounds of pears could he have bought for same amount of money?

(1) 1 pound of pears cost $0.5 more that 1 pound of apples.

If 1 pound of pears cost $1 and 1 pound of apples cost $0.5, then the cost of 5 pounds of apples is 5*0.5=$2.5. For $2.5 we can buy 2.5/1=2.5 pounds of pears.
If 1 pound of pears cost $1.5 and 1 pound of apples cost $1, then the cost of 5 pounds of apples is 5*1=$5. For $5 we can buy 5/1.5=10/3 pounds of pears.

Not sufficient.

(2) 1 pound of pears cost 1.5 times as much as 1 pound of apples. The cost of 5 pounds of apples is $5a (where a is the cost of 1 pound of apples). For $5a we can buy 5a/(1.5a)=5/1.5 pounds of pears. Sufficient.

Answer: B.

Hope it's clear.
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Re: Pat bought 5 pounds of apples. How many pounds of pears [#permalink] New post 10 Aug 2013, 13:17
Bunuel wrote:
fozzzy wrote:
I didn't understand statement 2


Pat bought 5 pounds of apples. How many pounds of pears could he have bought for same amount of money?

(1) 1 pound of pears cost $0.5 more that 1 pound of apples.

If 1 pound of pears cost $1 and 1 pound of apples cost $0.5, then the cost of 5 pounds of apples is 5*0.5=$2.5. For $2.5 we can buy 2.5/1=2.5 pounds of pears.
If 1 pound of pears cost $1.5 and 1 pound of apples cost $1, then the cost of 5 pounds of apples is 5*1=$5. For $5 we can buy 5/1.5=10/3 pounds of pears.

Not sufficient.

(2) 1 pound of pears cost 1.5 times as much as 1 pound of apples. The cost of 5 pounds of apples is $5a (where a is the cost of 1 pound of apples). For $5a we can buy 5a/(1.5a)=5/1.5 pounds of pears. Sufficient.

Answer: B.

Hope it's clear.



Hello Bunuel,

Can you please correct my approach of solving this question.

Statement 1:

5 pound of apple cost x
1 pound of apple cost x/5

1 pound of pear would have cost x/5 + 0.5$. Since x is unknown . Hence not sufficient

Statement 2:

1 pound of pear cost 3/2(x/5).

Here, now i thought that since x is still unknown its not sufficient.

Combining both also doesnt give value for x. Hence my answer was E which is incorrect,

Can you please solve this question using my approach. If its correct :) thanks!
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Re: Pat bought 5 pounds of apples. How many pounds of pears [#permalink] New post 01 Nov 2014, 12:19
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Re: Pat bought 5 pounds of apples. How many pounds of pears [#permalink] New post 26 Feb 2015, 15:00
Seen quite a number of DS problem of this type, when they give you ratio then most probably you can figure it out the values, (2) 3x = 2y. But if they simply give you data like (1) x = y + 0.5 then there are high chances you can't figure it out the answer.
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Re: Pat bought 5 pounds of apples. How many pounds of pears [#permalink] New post 26 Feb 2015, 20:15
Expert's post
Hi All,

While ankurjohar's question is over 1.5 years old, I'll still answer it because that approach COULD have worked, but the work was incomplete...

Based on that user's initial steps....

$X = cost of 5 pounds of apples
$X/5 = cost of 1 pound of apples

Fact 2 tells us that 1 pound of pears costs 1.5 times the cost of 1 pound of apples.

With some Algebra, we have...

(X/5) = cost of 1 pound of apples
(3/2)(X/5) = cost of 1 pound of pears
3X/10 = cost of 1 pound of pears

At this point, ankurjohar assumed that this was insufficient, but there's still more work to do....

We now have a ratio that relates what $X will buy you in this situation:

$X buys you 5 pounds of apples

Since $(3/10)(X) buys you 1 pound of pears, $X will buy you 10/3 pounds of pears, so we CAN answer the question with this information.
Fact 2 is SUFFICIENT.

Final Answer:
[Reveal] Spoiler:
B


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Re: Pat bought 5 pounds of apples. How many pounds of pears [#permalink] New post 26 Feb 2015, 20:26
it is typical when difference in values of one item is not sufficient to count total number of items, but their ratio is sufficient

B
Re: Pat bought 5 pounds of apples. How many pounds of pears   [#permalink] 26 Feb 2015, 20:26
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