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Pat will walk from intersection X to intersection Y along a [#permalink]
01 Aug 2003, 07:36

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Difficulty:

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Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

Pat will walk from intersection X to intersection Y along a route that is confined to the square grid of four streets and three avenues shown in the map above. How many routes from X to Y can Pat take that have the minimum possible length?

Can you show me the best way to attack path questions? _________________

Will come back to that other post on "GMAT Classic" later in the show.

Got something stuck in my head with expressing this simple division conretely.

Okay, Kpadama,

120 ways to travel this route ------------------------------- 12 ways to travel the shortest.

So every 12th way there is a shortest route. This brings the total to 10 different minimum routes. this sounds so foreign

Stolyar, I think your way is just a coincidence. Twist around the number of up and down roads and is quite a different way.

Stolyar is exactly correct.

If you do not take the shortest route than there are an infinite number of ways to get from A to B. _________________

Best,

AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993

My problem with it [#permalink]
01 Aug 2003, 12:44

There are 3 roads from Pittsburgh to Ocean City, Md and four roads from Ocean city, Md. to Bay City,CA. If Allison drives from Pittsburgh to Bay City, CA and back, passes from Ocean City in both directions, and does not travel any road twice, how many different routes for the trip are possible? You see in this similar problem, can anybody come up with permus or combos to solve it.

So, getting back to Kpadama's way, I guess we state there are five diff. roads. We start with the first road and can go five different ways, . I'm lost here.

Will come back to that other post on "GMAT Classic" later in the show.

Got something stuck in my head with expressing this simple division conretely.

Okay, Kpadama,

120 ways to travel this route ------------------------------- 12 ways to travel the shortest.

So every 12th way there is a shortest route. This brings the total to 10 different minimum routes. this sounds so foreign

Stolyar, I think your way is just a coincidence. Twist around the number of up and down roads and is quite a different way.

Stolyar is exactly correct.

If you do not take the shortest route than there are an infinite number of ways to get from A to B.

Dear AkamaiBrah & stolyar,

I beg to differ, even though I consider you both my Guru's, that if the
number are changed from 3&2 to 7&2, your approach will fail. In addition,
I don't think we can treat this problem as a simple combination one.
I would like to get your feedback?

After posting the previous response, I realised that I was wrong. I think, I am forgetting even simple addition and basic logic.

That's okay. By daring to challenge us, then realizing after thinking more carefully that you are wrong, you undoubtably understand this problem (and combinations in general) much better than if you were to just accept what we say and move on. It is good that you took the time to turn this around in your head a few times.

Good job. _________________

Best,

AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993

Originally posted on MIT Sloan School of Management : We are busy putting the final touches on our application. We plan to have it go live by July 15...