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# Penny Nickel Dime

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Senior Manager
Joined: 03 Mar 2010
Posts: 440
Schools: Simon '16 (M)
Followers: 5

Kudos [?]: 203 [0], given: 22

Penny Nickel Dime [#permalink]  12 May 2011, 00:04
00:00

Difficulty:

(N/A)

Question Stats:

67% (01:55) correct 33% (00:27) wrong based on 6 sessions
Sue has only pennies, dimes, and nickels in a jar. The jar has at least 1 but
no more than 4 pennies. If the jar has at least 1 nickel and 1 dime, which of the
following could NOT be the total amount of money in the jar?
A. 51 cents
B. 53 cents
C. 55 cents
D. 57 cents
E. 59 cents

I am bit confused. is this what question says:
1<=P<4
N<=1
D<=1
[Reveal] Spoiler: OA

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VP
Status: There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Joined: 08 May 2009
Posts: 1354
Followers: 15

Kudos [?]: 193 [0], given: 10

Re: Penny Nickel Dime [#permalink]  12 May 2011, 02:23
1 penny = 1 cent
1 dime = 10 cents
1 nickel = 5 cents

thus x* penny + y* 10(penny) + z* 5 penny = x + 10y + 5z = total cents

1. y=4,z=2,x=1
2. y=4,z=2,x=3
3. y=4,z= 2,x=5 not possible Hence C.
4. y=5,z=1,x=2
5. y=5,z=1,x=4

Thus C.
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Joined: 16 Nov 2010
Posts: 1675
Location: United States (IN)
Concentration: Strategy, Technology
Followers: 32

Kudos [?]: 413 [0], given: 36

Re: Penny Nickel Dime [#permalink]  12 May 2011, 04:23
51 = 4D + 2N + 1P
53 = 4D + 2N + 3P
55 = 4D + 2N + 5P or 5D + 1N (Not Possible)
57 = 5D + 1N + 2P
59 = 4P + 1N + 5D

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Re: Penny Nickel Dime   [#permalink] 12 May 2011, 04:23
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