Percent Word problem

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Percent Word problem [#permalink]

25 Feb 2011, 13:19

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Question Stats:

100% (01:35) correct

0% (00:00) wrong

based on 2 sessions

Jar Y has 10% more marbles than Jar X . What percent of marbles from Jar Y need to be moved into X so that both jars have equal marbles

4.54%

9.09%

10%

11%

12.25 %

[Reveal] Spoiler: OA

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Re: Percent Word problem [#permalink]

25 Feb 2011, 13:25

rxs0005 wrote:

Jar Y has 10% more marbles than Jar X . What percent of marbles from Jar Y need to be moved into X so that both jars have equal marbles

4.54%
9.09%
10%
11%
12.25 %

Best done with number plugging. Assume there are 100 marbles in jar X then in jar Y there will be 110 marbles. Now, both jars to have equal marbles we should move 5 marbles from Y to X, which is 5/110=~4.54% of Y.

Answer: A.
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Re: Percent Word problem [#permalink]

25 Feb 2011, 22:07

The answer coming from the calculation is 5 but the options we have doesn't matches with even one of the choices. Does this kind of choices are given in GMAT test also ?

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Re: Percent Word problem [#permalink]

26 Feb 2011, 00:23

mukgera wrote:

The answer coming from the calculation is 5 but the options we have doesn't matches with even one of the choices. Does this kind of choices are given in GMAT test also ?

No; the choices will be approximated only when GMAT question explicitly mentions that;

Here the answer is very close 4.54, not 5.

Jar Y has 10% more marbles than X
Y = 1.1X
If k marbles are taken out of Y. The remaining marbles in Jar Y= 1.1X-k
If k marbles are added to X. The new marbles' count in Jar X= X+k

And we know they are equal;

X+k = 1.1X-k
2k = 0.1X
k= 0.05X

The marbles taken out of Y = 0.05X
Question is: 0.05X is what percent of marbles that was originally there in Y i.e. 1.1X

\frac{0.05X}{1.1X}*100

\frac{0.05X}{1.1X}*100

\frac{50}{11} = 4.\bar{54} \approx 4.54

Sol: "A"
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Re: Percent Word problem [#permalink]

26 Feb 2011, 00:38

thanks fluke for the explanation

Re: Percent Word problem [#permalink] 26 Feb 2011, 00:38

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