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09 Sep 2010, 01:26
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Two identical taps fill 2/5 of a tank in 20 minutes. When one of the taps goes dry in how many minutes will the remaining one tap fill the rest of the tank ?
A. 5 minutes
B. 10 minutes
C. 15 minutes
D. 20 minutes

ANS SHUD BE 15 MINS
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09 Sep 2010, 01:43
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Hi Silpajorna,
Welcome to the GMAT club..can u plz check out this question again?
i doubt coz since accd to ur question together they are taking 2/5 to fill in 20 min so rest 3/5 together they will take 30 min more.... if i remove one then it will take more time?
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09 Sep 2010, 01:51
They are identical taps so each of them fills 1/5 of the tank in 20 minutes.

There are 3/5 remaining, so it will take 60 minutes (20 minutes for each 1/5) to fill the rest.
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09 Sep 2010, 09:24
rid82 wrote:
They are identical taps so each of them fills 1/5 of the tank in 20 minutes.

There are 3/5 remaining, so it will take 60 minutes (20 minutes for each 1/5) to fill the rest.

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09 Sep 2010, 10:22
A quick point here - from the way the question is worded, we don't even know "when" the first tap stops, as "when" begins a new sentence:

Two identical taps fill 2/5 of a tank in 20 minutes. When one tap stops, how long will it take the other to finish the tap?

Those two sentences are two completely separate thoughts - the first gives us an indication of the combined rate, and the second asks a question. But we don't know at which point the first tap stops - it could be after the tank is half full, or after 30 minutes, or at any other point. That next step is what's missing from this question.
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09 Sep 2010, 10:34
true. yeah its just a bad question overall i think. but that's just me.
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12 Sep 2010, 13:31
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If we assume the tap stops after 20 min. Then I guess answer would be - only tap running will take 60 more minutes to fill the tank
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13 Sep 2010, 02:10
60 minutes if one tap is closed at 2/5 tank
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