tennis_ball wrote:

first step:

work out the total #:

every day he can select any of them which are independent:

3 * 2 * 3.

and each day is also independent from each other, so for 3 days, you have:

(3*2*3)^3.

This is the total # that'll be the denominator.

Second step:

find the desired #:

Since shoes for 3 days don't change, so for shoes u have 2 choices for all 3 days:

2.

Shirts change every day and no repeat, it is a permutation of all the 3 shirts. so it is 3!.

pants are the same as shirts are. so also 3!.

shoes, shirts and pants are independent from one another, so multiply them:

2*3!*3!.

so the prob:

2*3!*3!/ (3*2*3)^3. u get the answer.

Shirts change every day and no repeat, it is a permutation of all the 3 shirts. so it is 3!.
Why are arranging shirts...You should be rather picking ie a combination should come right?

Where am I thinking wrong tennis?