Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 03 Jul 2015, 14:07

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

Author Message
TAGS:
Intern
Joined: 01 Jun 2010
Posts: 5
Followers: 0

Kudos [?]: 0 [0], given: 0

00:00

Difficulty:

(N/A)

Question Stats:

100% (01:32) correct 0% (00:00) wrong based on 0 sessions
When two dice are thrown, what is the probability that the score on the second dice is higher than the score on the first dice?

[Reveal] Spoiler:
5/12

Intern
Joined: 01 Jun 2010
Posts: 5
Followers: 0

Kudos [?]: 0 [0], given: 0

I understand now

1) First dice: 1 ... Second dice: 2, 3, 4, 5, or 6 ... P=(1/6)*(5/6)
2) First dice: 2 ... Second dice: 3, 4, 5, or 6 ... P=(1/6)*(4/6)
3) First dice: 3 ... Second dice: 4, 5, or 6 ... P=(1/6)*(3/6)
4) First dice: 4 ... Second dice: 5 or 6 ... P=(1/6)*(2/6)
5) First dice: 5 ... Second dice: 6 ... P=(1/6)*(1/6)

The sum of probabilities of the 5 scenarios: 15/36
Math Expert
Joined: 02 Sep 2009
Posts: 28272
Followers: 4469

Kudos [?]: 45130 [0], given: 6645

Expert's post
test800 wrote:
When two dice are thrown, what is the probability that the score on the second dice is higher than the score on the first dice?

[Reveal] Spoiler:
5/12

There are 6*6=36 possible outcomes when you throw 2 dice.

In 6 of these outcomes there will be a tie (1-1, 2-2, 3-3, ..., 6-6). 30 outcomes left: now in half of these outcomes (30/2=15) the score of die #1 will be more than the score of die #2 and in another half of the outcomes the score of die #1 will be less than the score of die #2. So $$P(#2>#1)=\frac{15}{36}=\frac{5}{12}$$.

Answer: $$\frac{5}{12}$$.

Hope it helps.
_________________
Similar topics Replies Last post
Similar
Topics:
Pls help (Probability w. dice) 3 07 Jun 2010, 05:46
Probability n-sided dice 3 03 Jun 2010, 00:51
Two dice are rolled. What is the probability the sum will be 7 26 Jan 2006, 17:38
Display posts from previous: Sort by