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Please Show me the way to solve this type of math....

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Please Show me the way to solve this type of math.... [#permalink] New post 28 Oct 2011, 23:06
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In a nationwide poll, P people were asked 2 questions. In 2/5 answered “yes” to question 1, and of those 1/3 also answered yes to question 2, which of the following represents the number of people polled who did not answer “yes” to both questions ?
a) 11/13
b) 3/16
c) 13/15
d) 2/15
e) None of these
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Re: Please Show me the way to solve this type of math.... [#permalink] New post 29 Oct 2011, 00:22
aselfmademan wrote:
In a nationwide poll, P people were asked 2 questions. In that 2/5 answered “yes” to question 1, and of those 1/3 also answered yes to question 2, which of the following represents the number of people polled who did not answer “yes” to both questions ?
a) 11/13
b) 3/16
c) 13/15
d) 2/15
e) None of these


People answered Yes to Q1 = 2/5
People who answered Yes to Q2 = 1/3 of people who answered yes to Q1 (People who answered Yes to both Questions)
= 1/3(2/5)
2/15

So People who did not answer Yes to both Questions = People participated in the poll - People who answered Yes to both Questions
=1-2/15
=13/15
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Re: Please Show me the way to solve this type of math.... [#permalink] New post 29 Oct 2011, 01:04
aselfmademan wrote:
In a nationwide poll, P people were asked 2 questions. In 2/5 answered “yes” to question 1, and of those 1/3 also answered yes to question 2, which of the following represents the number of people polled who did not answer “yes” to both questions ?
a) 11/13
b) 3/16
c) 13/15
d) 2/15
e) None of these


If you are not comfortable with algebra, you can substitute suitable values in place of variables.
Let's say p = 30 (i.e. only 30 people were surveyed)
Out of these 30, 2/5 said 'yes' to Q1. This implies 2/5*30 = 12 said 'Yes' and thus 18 said 'No'
Out of these 12, 1/3 said 'yes' to Q2 as well. This implies 1/3*12 = 4 said 'yes' to both Q1 and Q2.
Thus the remaining 26 people would not have said "yes" to both questions and our ratio is 26/30 = 13/15
Hence (C)
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Re: Please Show me the way to solve this type of math.... [#permalink] New post 29 Oct 2011, 04:01
Thanks both of you.... :-D
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Re: Please Show me the way to solve this type of math.... [#permalink] New post 29 Oct 2011, 05:37
Nice way to solve it Nirav
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Re: Please Show me the way to solve this type of math.... [#permalink] New post 29 Oct 2011, 18:50
My working is:

2/5(1/3) = 2/15 ppl who answer yes to both
So people who don't answer yes to both = 1/2/15 = 13/15

However..I was a bit confused at first. How do we know that the people who answer NO to the first question won't say YES to the second question?
Is that because "and of those 1/3 also answered yes to question 2" so we can assume only the 2/5 who said yes to the first question are the only peopel who say YES to the second question?

Haha thanks giving a answer and asking a question...any thoughts anyone? Thanks!
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Re: Please Show me the way to solve this type of math....   [#permalink] 29 Oct 2011, 18:50
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