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Pls help me to solve this problem.(3)

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Pls help me to solve this problem.(3) [#permalink] New post 31 Jul 2011, 03:35
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Question Stats:

80% (01:29) correct 20% (00:00) wrong based on 0 sessions
1/2^10+1/2^11+1/2^12+1/2^12 =


a)1/2^7
b)1/2^8
c)1/2^9
d)1/2^13
e)1/2^45

is there any simple way to solve this kind of problem?
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Re: Pls help me to solve this problem.(3) [#permalink] New post 31 Jul 2011, 05:39
tracyyahoo wrote:
is there any simple way to solve this kind of problem?


Yes.

1/2^1^0+1/2^1^1+1/2^1^2+1/2^1^2
=1/2^1^0 + 1/2^1^1 + 2/2^1^2
= 1/2^1^0 + 1/2^1^1 + 1/2^1^1
= 1/2^1^0 + 2/2^1^1
= 1/2^1^0 + 1/2^1^0
= 2/2^1^0
= 1/2^9

Mere addition.
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Re: Pls help me to solve this problem.(3) [#permalink] New post 31 Jul 2011, 18:25
Yeah, Thank you. It is a simple way.


jamifahad wrote:
tracyyahoo wrote:
is there any simple way to solve this kind of problem?


Yes.

1/2^1^0+1/2^1^1+1/2^1^2+1/2^1^2
=1/2^1^0 + 1/2^1^1 + 2/2^1^2
= 1/2^1^0 + 1/2^1^1 + 1/2^1^1
= 1/2^1^0 + 2/2^1^1
= 1/2^1^0 + 1/2^1^0
= 2/2^1^0
= 1/2^9

Mere addition.
OA C
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Re: Pls help me to solve this problem.(3) [#permalink] New post 09 Aug 2011, 07:20
tracyyahoo wrote:
1/2^10+1/2^11+1/2^12+1/2^12 =


a)1/2^7
b)1/2^8
c)1/2^9
d)1/2^13
e)1/2^45

is there any simple way to solve this kind of problem?


HI Tracee,
You can also solve the problem by taking factors like shown below:

1/2^10+1/2^11+1/2^12+1/2^12
= 1/2^12[2^2+2+1+1] (taking 1/2^12 common)
= 1/2^12(8)
=1/2^9

Hence C
Re: Pls help me to solve this problem.(3)   [#permalink] 09 Aug 2011, 07:20
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