Pls need your quick way!
Just realize that the first is solvable. Yes if you solve it. You get r=10.
But no reason to.
Stmt2: there are numerous values. Try 8 for r.
We get the solution as 1.1664>1.15. Thus we can have many values.
everyone cracked the first one , for second statement I will use this approach which I think is quicker
(1+r/100)^2 > 1.15
expanding the left side and representing the right side to match the left side will make it much easier
(1 + 2r/100 + r^2/10000) > 1 + 15/100
r^2/10000 is way too small so ignore that term , you can think of the above statement as
(1 + 2r/100 ) > 1 + 15/100
which means 2r> 15 and r>7.5 (not > 8) , so insuff ....