pls provide the detailed solution : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 24 Jan 2017, 16:31

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# pls provide the detailed solution

Author Message
VP
Joined: 18 May 2008
Posts: 1286
Followers: 16

Kudos [?]: 411 [0], given: 0

pls provide the detailed solution [#permalink]

### Show Tags

23 Jun 2008, 22:25
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

pls provide the detailed solution
Attachments

shortest path.doc [25.5 KiB]

SVP
Joined: 17 Jun 2008
Posts: 1569
Followers: 11

Kudos [?]: 250 [0], given: 0

### Show Tags

23 Jun 2008, 22:48

If I name the various corners as follows

10 11 12
7 8 9
4 5 6
1 2 3

Then, the following are the possible routes (the shortest routes will be going horizontal and vertical only):

1-2-3-6-9-12
1-2-5-6-9-12
1-2-5-8-9-12
1-2-5-8-11-12
1-4-5-6-9-12
1-4-5-8-9-12
1-4-5-8-11-12
1-4-7-8-9-12
1-4-7-8-11-12
1-4-7-10-11-12

If there is any short cut to this, please let me know.
Current Student
Joined: 12 Jun 2008
Posts: 287
Schools: INSEAD Class of July '10
Followers: 7

Kudos [?]: 52 [0], given: 0

### Show Tags

24 Jun 2008, 00:48

To go from X to Y, you have to take 5 segments. 3 vertical segments and 2 horizontal segments in any order you want.

So this is just a matter of choosing (for instance) which of the 2 segments amongst the 5 will be horizontal segments.

Number is $$2C5=\frac{5!}{3!*2!}=10$$
VP
Joined: 18 May 2008
Posts: 1286
Followers: 16

Kudos [?]: 411 [0], given: 0

### Show Tags

24 Jun 2008, 02:14
Wow Oski ! u rock! Answer is 10 indeed. thanks a lot!
Oski wrote:

To go from X to Y, you have to take 5 segments. 3 vertical segments and 2 horizontal segments in any order you want.

So this is just a matter of choosing (for instance) which of the 2 segments amongst the 5 will be horizontal segments.

Number is $$2C5=\frac{5!}{3!*2!}=10$$
Re: PS: shortest path   [#permalink] 24 Jun 2008, 02:14
Display posts from previous: Sort by