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25 Sep 2007, 15:07
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pls see the attachment.
Current Student
Joined: 31 Aug 2007
Posts: 369
Followers: 1

Kudos [?]: 101 [0], given: 1

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25 Sep 2007, 15:11
hmm does not seem to be working...so I will jsut type it out.

each employee on a certain task force is either a manager or director. what % of the employees on the task force are directors?

s1-the avg salary of the managers on the task force is 5000 less than the avg salary of all employees on the task force
s2-the avg salary of the directors on the task force is 15000 greater than the avg salary of all employees on the task force.

Thanks!
Current Student
Joined: 31 Aug 2007
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25 Sep 2007, 17:18
OA is C
i'm getting 25% are directors...
Manager
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29 Sep 2007, 03:03
I got this wrong in the GMATPrep. Can you believe I spent 8 mins on this Q and yet got it wrong eventhough I managed to make-up after this mess & recovered to get 760 in GMATPrep test. But I cannot afford to waste time like this in the actual exam. Not being able to let go is my biggest enemy and that problem is not allowing me to finish the Quant section in time.

Hence I am trying to ensure that I understand the concept behind solving this one once and for all. Actually the problem is not at all difficult once one understands the concept behind it. While I did setup the equations correctly in the test, where I went wrong was that I over-simplified the equation from the beginning. eg. Avg=Sum/No. There is no need for this simplification. Here is how it should have been solved. Don't mind the extra no. of steps. That's just for my own understanding. The actual solution should not take more than 2 mins.

Let M=No of managers, D=No. of Directors. Therefore, M+D=All employees.
Let AM=Avg Sal of Managers, AD=Avg Sal of Directors & A(M+D)=Avg sal of all employees.

St1: AM=A(M+D) - 5000
Sum of Sal of all Managers = M*AM = M*(A(M+D) - 5000)=M*A(M+D) - 5000M
Insufficient

Sum of Sal of all Directors = D*AD = D*(A(M+D) + 15000)=D*A(M+D) + 15000D
Insufficient

St1 & St2 when combined yields the equation.
Sum of Sal of all Employees = A(M+D)*(M+D)
Also Sum of Sal of all Employees = Sum of Sal of all Managers + Sum of Sal of all Directors

Therefore, A(M+D)*(M+D) = M*A(M+D) - 5000M + D*A(M+D) + 15000D
i.e. 5000M = 15000 D
i.e. D/M = 1/3
i.e. D/(M+D) = 1/4 = 25%

Hence C.
_________________

Regards

Subhen

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