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# Plz help me with this PS prob

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Intern
Joined: 24 Jun 2009
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Plz help me with this PS prob [#permalink]  24 Jun 2009, 06:31
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All of the stock on over-the-counter market are designated by either a 4-letter or 5-letter code that is created by using the 26 letters of the alphabet. which of the following gives the maximum number of different stocks that can be designated with these codes?
a 2(26^5)
b 26(26^4)
c 27(26^4)
d 26(26^5)
e 27(26^5)

thanks
Current Student
Joined: 03 Aug 2006
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Re: Plz help me with this PS prob [#permalink]  24 Jun 2009, 08:32

$$\text {No of 4 letter codes} = 26\times 26\times 26\times 26 = 26^4$$

$$\text {No of 5 letter codes} = 26\times 26\times 26\times 26\times 26= 26^5$$

$$\text {Total number of codes} = 26^4 + 26^5 = 26^4 (1+26)= 26^4 (27)$$

See the post below that has a similar problem.

permutations-s-79747.html
Re: Plz help me with this PS prob   [#permalink] 24 Jun 2009, 08:32
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