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Point (a,b) is on the circle represented by x^2+y^2=10, [#permalink]
 04 Jan 2013, 05:41
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Point (a,b) is on the circle represented by x^2+y^2=10, and a, b are integers. How many such points are possible? A. 0 B. 2 C. 4 D. 6 E. 8
Last edited by Bunuel on 04 Jan 2013, 05:45, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Point (a,b) is on the circle represented by x^2+y^2=10, [#permalink]
04 Jan 2013, 05:53
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trex16864 wrote: Point (a,b) is on the circle represented by x^2+y^2=10, and a, b are integers. How many such points are possible?
A. 0
B. 2
C. 4
D. 6
E. 8 a^2+b^2=10 and a, b are integers means that 10 is the sum of two perfect squares. 10 is the sum of only one pair of perfect squares 1 and 9. So, there can be 8 such points, 4 in each quadrant: (1, 3); (1, -3); (-1, 3); (-1, -3); (3, 1); (3, -1); (-3, 1); (-3, -1). Answer: E.
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Re: Point (a,b) is on the circle represented by x^2+y^2=10, [#permalink]
04 Jan 2013, 07:47
X and Y are integers and when squared have to equal 10. X and Y can take values of 1,3,-1,-3. The 1 and the 3 must be used in combination in order to add up to 10 (you cant use 1,1 or 3,3 or -1,-1, or -3,-3).
this leaves you with only 8 choices. answer E
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Re: Point (a,b) is on the circle represented by x^2+y^2=10, [#permalink]
05 Jan 2013, 00:20
Very gmatlike question.Can u tell us the source?
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Re: Point (a,b) is on the circle represented by x^2+y^2=10,
[#permalink]
05 Jan 2013, 00:20
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