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Positive integer n leaves a remainder of 4 after division by

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Re: Manhattan Remainder Problem [#permalink] New post 03 Nov 2012, 14:14
Bunuel wrote:
To elaborate more.

Suppose we are told that:
Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 2 after division by 8. What is the remainder that n leaves after division by 12?

The statement "positive integer n leaves a remainder of 4 after division by 6" can be expressed as: n=6p+4. Thus according to this particular statement n could take the following values: 4, 10, 16, 22, 28, 34, 40, 46, 52, 58, 64, ...

The statement "positive integer n leaves a remainder of 2 after division by 8" can be expressed as: n=8q+2. Thus according to this particular statement n could take the following values: 2, 10, 18, 26, 34, 42, 50, 58, 66, ...

The above two statements are both true, which means that the only valid values of n are the values which are common in both patterns. For example n can not be 16 (from first pattern) as the second formula does not give us 16 for any value of integer q.

So we should derive general formula (based on both statements) that will give us only valid values of n.

How can these two statement be expressed in one formula of a type n=kx+r? Where x is divisor and r is a remainder.

Divisor x would be the least common multiple of above two divisors 6 and 8, hence x=24.

Remainder r would be the first common integer in above two patterns, hence r=10.

Therefore general formula based on both statements is n=24k+10. Thus according to this general formula valid values of n are: 10, 34, 58, ...

Now, n divided by 12 will give us the reminder of 10 (as 24k is divisible by 12).

Hope it helps.



Hi Bunuel, I had a quick question with this explanation:

Do we have to find the LCM? I just multiplied 6 x 8 and got 48 => n = 48k + 10 which also leads to a remainder of 10.
My question is is finding the LCM necessary?
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Re: Positive integer n leaves a remainder of 4 after division by [#permalink] New post 16 Dec 2012, 14:22
n=24k+10=12(12k)+10 --> n can be: 10, 34, 58, ... n divided by 12 will give us the reminder of 10.

As, you can see, n divided by 14 can give different remainders. If n=10, then n divided by 14 yields the remainder of 10 but if n=34, then n divided by 14 yields the remainder of 6.

Bunuel - Can you please explain this? how does 24k+10 = 12(12k)+10

and can you help me to visualize how you would divide 24k+10 by 12? thanks!
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Re: Positive integer n leaves a remainder of 4 after division by [#permalink] New post 16 Dec 2012, 23:29
jmuduke08 wrote:
n=24k+10=12(12k)+10 --> n can be: 10, 34, 58, ... n divided by 12 will give us the reminder of 10.

As, you can see, n divided by 14 can give different remainders. If n=10, then n divided by 14 yields the remainder of 10 but if n=34, then n divided by 14 yields the remainder of 6.

Bunuel - Can you please explain this? how does 24k+10 = 12(12k)+10

and can you help me to visualize how you would divide 24k+10 by 12? thanks!


It's n=24k+10=12*2k+10, not n=24k+10=12*12k+10.
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Re: Positive integer n leaves a remainder of 4 after division by [#permalink] New post 18 Dec 2012, 01:40
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since n is greater than 30 we check for the number which gives a remainder of 4 after dividing by 6 and 3 after dividing by 5 , the number comes out to 58. So it will give a remainder of 28 after dividing by 30. Answer (E).
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Re: Positive integer n leaves a remainder of 4 after division by   [#permalink] 18 Dec 2012, 01:40
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