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Possible ways tp open the door (Permutation/Combination) [#permalink]
12 Mar 2009, 16:07
This topic is locked. If you want to discuss this question please re-post it in the respective forum.
A door can be opened only with a security code that consists of five buttons: 1, 2, 3, 4, 5. If, to open the door you must press three codes, then how many possible ways are there to open the door? Assume that the same code may be repeated. _________________
Re: Possible ways tp open the door (Permutation/Combination) [#permalink]
14 Mar 2009, 08:03
botirvoy wrote:
sandipchowdhury wrote:
As same codes can be repeated my answer is =5*5*5= 125
agree.
Disagree: you have 5! possibilities each time you type in a code (having the same code purely means you don't have to subtract duplicates which makes the question easier). Thus 5! x 5! x 5! is the correct answer.
Re: Possible ways tp open the door (Permutation/Combination) [#permalink]
15 Mar 2009, 02:34
Ok now my take seems to be completely different on this one. Plz point out the flaw if any:
Since there are 5 numbers in a given code and there are 5 numbers, I think the total posssible codes are: 5*5*5*5*5 = 3125. No where in the question does it say that you are not allowed to repeat the same digit in the code.
Now since the codes can be repeated, 3125 is the number of code possible without combination. We will have to add this figure to the one possible with combination.
Now to select 3 codes out of 3125, we should use the combination formula. C(3125, 3). Now this yields a huge figure ( 3123*3124*3125)/6
This should be added to the prev figure, ie, total possibilities: 3125 + ( 3123*3124*3125)/6.
Now my concern is the magnitude of the solution. Rarely do I see such an insane answer.
Please provide the official answer and if someone can point out any flaw in the reasoning above, please let me know.
Re: Possible ways tp open the door (Permutation/Combination) [#permalink]
15 Mar 2009, 02:48
Expert's post
krishan wrote:
A door can be opened only with a security code that consists of five buttons: 1, 2, 3, 4, 5. If, to open the door you must press three codes, then how many possible ways are there to open the door? Assume that [color=#BF0000]the same code may be repeated[/color].
5 possibilities for each pressed button: 5*5*5=125 ways. The problem is poorly written or I don't understand how to press three codes that consist of five buttons: 1) "a security code that consists of five buttons" - a code cannot consists of 5 buttons, can it? 2) "must press three codes" - maybe buttons? _________________