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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
1) yes ---> 3.3 --> 50th--> 98.0.

2) yes ---> at least 3rd ---> line black

3) no ----> at least 85% line green -----> no
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
carcass wrote:
1) yes ---> 3.3 --> 50th--> 98.0.

2) yes ---> at least 3rd ---> line black

3) no ----> at least 85% line green -----> no



the definition is as nth percentile in height for a given age is the unique height among boys of that age that is greater than or equal to n percent, and less than or equal to (100- n) percent

so for Q.A : how can you be sure that the probability is greater than 50%
it can be 50% as well, right?
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
your area where you are looking for your answer ;) > 3.3......so 3.6 and so on......
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
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For question 1 isn't this scenario possible
:Let age be 3.6 and 98cms correspond to 49 percentile.
because in the first graph Age 3.6 and height 99.9 corresponds to 50th percentile so isn't it also possible that 98cms may be in the 49th percentile.
Please see the attached table illustrating this scenario.
Can some expert please point out why in table 3.1 the scenario highlighted in Green in not possible?

In the table above I have just added two more percentiles 45th and 49th in between 15th and 50th, and two single month increments between ages 3.3 and 3.6. This extra data has been highlighted in Grey.
The table is consistent with the rest of the data given in the original table.
There is an increment in height as we go from left to right and also there is an increment in height as we go from top to bottom.

Question 1 states:
A. If his age is greater than 3 years 3 months; the probability that his height is at least 98.0 cm is greater than 50%.

if we look at the table then the scenario in green is a possibility is it not? The scenario in green states that, at age 3.6 if height is 98.0 then it is in the 49th percentile.

So height 98cms at age greater than 3.3 need not be greater than 50th percentile.

So if the scenario in the table above is possible then answer to question 1 need NOT be yes.
Can experts please tell why the scenario in Green in not possible?

Thank you.
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
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Bunuel Can you please help with Baybeam's questions? Thanks in advance!
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
Bloddy Helll!!! Can anyone please explain the prompt in simple english ????
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
Sajjad1994

Why did you skip #2?
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
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GK002 wrote:
Sajjad1994

Why did you skip #2?


Hi GK002

Unfortunately, I do not have the OE of question #2.

I have posted the OEs from the EA course and the course skipped question #2.
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
Can anyone post the answer for Question 2
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
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6. Consider an individual boy from a model population. Suppose that from age 2 through age 5, this boy’s weight is at the 50th percentile for his height and his height is at the 50th percentile for his age. Which one of the following statements must be true of the boy at age 5 years 0 months?

Neither Height-for-age standards nor Weight-for-height standards provide a distribution of age on the basis of weight, height, or any other variable, so it is impossible to determine where the boy's age falls in the distribution of age for height (option A).


Based on this explanation, the OA for Q2 CANNOT be A.

Q2 and Q6 are basically the same kind of questions. Here's OE for Q2:

Neither Height-for-age standards nor Weight-for-height standards provide a distribution of age on the basis of weight, height, or any other variable, so it is impossible to determine where the boy's age falls in the distribution of age for height (choice A).

The boy's weight is less than that of 97% of boys his height, and his height is less than that of 97% of boys his age, but it is impossible to tell where his weight falls among the weights of boys his age (choice B).

Likewise, knowing height-for-weight percentiles does not provide information about weight-for-height percentiles (choice C).

However, it is possible to approximate his height at each age and his weight at each height; thus it is possible to determine his weight at each age. Height-for-age standards indicates that at age 2 years 0 months, the boy was 92.9 cm tall, and at age 5 years 0 months, he was 118.7 cm tall. Weight-for-height standards indicates that the 97th percentile weight for boys 92.9 cm tall is approximately 16 kg, while the 97th percentile weight for boys 118.7 cm tall is between 26 kg and 27 kg. Thus his weight at age 5 years 0 months is roughly between 26/16 = 162 .5% and 27/16 = 168 .75%, or approximately 166%, of his weight at age 2 years 0 months.

The correct answer is D.
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
Sajjad1994 Can you please explain why Option B in Q2 is incorrect. The question states that the weight and the height are at 97 percentile, but the OE changes them to less than 97
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
Why are we unable to infer height based on weight using the weight-for-height graph? Does that graph not display height on the basis of weight and vice versa?
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
hi Sajjad1994 and other experts,

it its tough for me to understand this sentence
In a model population, for n = 3, 15, 50, 85, and 97, the nth percentile in weight for a given height is the unique weight among boys of that height that is greater than or equal to n percent, and less than or equal to (100 - n) percent, of weights of boys of that height.

would you please help clarify further?

thanks in advance
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
zoezhuyan wrote:
hi Sajjad1994 and other experts,

it its tough for me to understand this sentence
In a model population, for n = 3, 15, 50, 85, and 97, the nth percentile in weight for a given height is the unique weight among boys of that height that is greater than or equal to n percent, and less than or equal to (100 - n) percent, of weights of boys of that height.

would you please help clarify further?

thanks in advance

­Hi. This basically implies that if I say I am 97 percentile in weight, then 97 percent of people of my age will be equal to or less than my weight and 3 (100-97) percent of people of my age will have a weight greater than mine. They have basically tried to overcomplicate the definition of percentile.

If I say that my weight is 100 grams and it is 60 percentile. Then, 40 percent of people are heavier than 100 grams, while 60 percent people are 100 grams or less.
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Re: The World Health Organization (WHO) has produced a comprehensive set o [#permalink]
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