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1/(1+1/3)-1/(1+1/2)

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Bunuel
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1/(1+1/3)-1/(1+1/2) [#permalink] New post   26 Aug 2012, 02:59
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00:00
A
B
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D
E

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5% (low)

Question Stats:

93% (00:42) correct 7% (01:10) wrong based on 2919 sessions
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\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
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D
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Bunuel
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   26 Aug 2012, 02:59
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SOLUTION:

\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}=\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}=\frac{3}{4}-\frac{2}{3}=\frac{1}{12}\).

Answer: D.
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   26 Aug 2012, 08:22
By taking the LCM and taking the reciprocals-

3/4-2/3=1/12
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   27 Aug 2012, 11:07
Ans = (3/4) - (2/3) = 1/12
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   28 Aug 2012, 04:10
Answer is 1/12

3/4 - 2/3 = 1/12
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   28 Aug 2012, 08:28
bunuel.. i think difficulty level shud be 500 or below 500..

its 1/12.. person shud knw the 1+1/3 = 4/3.. by not taking LCM because that will waste ur time..
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   10 May 2016, 18:18
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Attached is a visual that should help.
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Screen Shot 2016-05-10 at 5.50.27 PM.png
Screen Shot 2016-05-10 at 5.50.27 PM.png [ 75.73 KiB | Viewed 45047 times ]

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UttamGiet
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   11 May 2016, 02:59
1/(4/3)-1/(3/2)= 3/4- 2/3= 9-8/12=1/12
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   16 Sep 2019, 09:37
Bunuel wrote:
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

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Question: 27
Page: 155
Difficulty: 550


\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}} = \frac{3}{4} - \frac{2}{3} = \frac{9 -8}{12} = \frac{1}{12}\)

IMO D
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   08 Jun 2021, 09:01
1/(4/3)-1/(3/2)= 3/4- 2/3= 9-8/12=1/12
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink] New post   31 Jan 2023, 23:01
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Re: 1/(1+1/3)-1/(1+1/2) [#permalink]
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