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Re: There are six consecutive positive integers in Set S. What [#permalink]
EvaJager wrote:
When dividing a positive integer by the positive integer \(n\), there are \(n\) possible remainders:
\(0,1,2,...,n-1\).

(1) If \(n=4\), the remainders are \(0,1,2,3,0,1,2,3...\) We can have a sequence of remainders \(2,3,0,1,2,3\) with a sum of \(11.\)
If \(n = 5\), the remainders are \(0,1,2,3,4,0,1,2,3,4,...\) We can have a sequence of remainders \(1,2,3,4,0,1\) again with a sum of \(11.\)
Not sufficient.

(2) We have 6 numbers in our sequence and only 5 distinct remainders, so necessarily \(n=5.\)
And as we have seen above, the remainders \(1,2,3,4,0,1\) give the sum of \(11.\)
Sufficient.
Answer B.


Thanks EvaJager. Understood
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Re: There are six consecutive positive integers in Set S. What [#permalink]
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Hi

B) if set S=0,1,2,3,4,5 then 5 will be the integer which gives the remainders include FIVE DIFFERENT VALUES
How about if S=1,2,3,4,5,6 then 6 too meet the criteria that is FIVE DIFFERENT VALUES
In the same manner
2,3,4,5,6,7 - 7
3,4,5,6,7,8 - 8
Please clarify...?
Thanks in advance...

Posted from my mobile device
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Re: There are six consecutive positive integers in Set S. What [#permalink]
4MBA wrote:
Hi

B) if set S=0,1,2,3,4,5 then 5 will be the integer which gives the remainders include FIVE DIFFERENT VALUES
How about if S=1,2,3,4,5,6 then 6 too meet the criteria that is FIVE DIFFERENT VALUES
In the same manner
2,3,4,5,6,7 - 7
3,4,5,6,7,8 - 8
Please clarify...?
Thanks in advance...

Posted from my mobile device



bb VeritasKarishma Bunuel Other experts; please help
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Re: There are six consecutive positive integers in Set S. What [#permalink]
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vansh789 wrote:
4MBA wrote:
Hi

B) if set S=0,1,2,3,4,5 then 5 will be the integer which gives the remainders include FIVE DIFFERENT VALUES
How about if S=1,2,3,4,5,6 then 6 too meet the criteria that is FIVE DIFFERENT VALUES
In the same manner
2,3,4,5,6,7 - 7
3,4,5,6,7,8 - 8
Please clarify...?
Thanks in advance...

Posted from my mobile device



bb VeritasKarishma Bunuel Other experts; please help


If S is {1, 2, 3, 4, 5, 6} and n = 6, then when each integer in S is divided by 6 we get the following remainders: 1, 2, 3, 4, 5, and 0, respectively. SIX different values.

If S is {2, 3, 4, 5, 6, 7} and n = 7, then when each integer in S is divided by 7 we get the following remainders: 2, 3, 4, 5, 6, and 0, respectively. SIX different values.

If S is {3, 4, 5, 6, 7, 8} and n = 8, then when each integer in S is divided by 8 we get the following remainders: 3, 4, 5, 6, 7, and 0, respectively. SIX different values.

Hope it's clear.
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Re: There are six consecutive positive integers in Set S. What [#permalink]
1
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4MBA wrote:
Hi

B) if set S=0,1,2,3,4,5 then 5 will be the integer which gives the remainders include FIVE DIFFERENT VALUES
How about if S=1,2,3,4,5,6 then 6 too meet the criteria that is FIVE DIFFERENT VALUES
In the same manner
2,3,4,5,6,7 - 7
3,4,5,6,7,8 - 8
Please clarify...?
Thanks in advance...

Posted from my mobile device


Also, remember that when any positive integer is divided by n, the remainder can take one of n unique values (0 or 1 or 2 or ... or (n-1))

So when any positive integer is divided by 5, the remainder can take one of 5 values (0/1/2/3/4)
When any positive integer is divided by 6, the remainder can take one of 6 values (0/1/2/3/4/5)
and so on...
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Re: There are six consecutive positive integers in Set S. What [#permalink]
Bunuel wrote:
vansh789 wrote:
4MBA wrote:
Hi

B) if set S=0,1,2,3,4,5 then 5 will be the integer which gives the remainders include FIVE DIFFERENT VALUES
How about if S=1,2,3,4,5,6 then 6 too meet the criteria that is FIVE DIFFERENT VALUES
In the same manner
2,3,4,5,6,7 - 7
3,4,5,6,7,8 - 8
Please clarify...?
Thanks in advance...

Posted from my mobile device



bb VeritasKarishma Bunuel Other experts; please help


If S is {1, 2, 3, 4, 5, 6} and n = 6, then when each integer in S is divided by 6 we get the following remainders: 1, 2, 3, 4, 5, and 0, respectively. SIX different values.

If S is {2, 3, 4, 5, 6, 7} and n = 7, then when each integer in S is divided by 7 we get the following remainders: 2, 3, 4, 5, 6, and 0, respectively. SIX different values.

If S is {3, 4, 5, 6, 7, 8} and n = 8, then when each integer in S is divided by 8 we get the following remainders: 3, 4, 5, 6, 7, and 0, respectively. SIX different values.

Hope it's clear.


Thanks a lot for your reply. Yes, I understand this; thank you!
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Re: There are six consecutive positive integers in Set S. What [#permalink]
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