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Re: The mode of a set of integers is x. what is the difference [#permalink]
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ChrisGMATPrepster wrote:
This question seems to be flawed in my mind.

Statement 1 intends to tell you that this is a consecutive set of multiples of 3 (the consecutive nature would make the mean equal to the median)

Statement 2 intends to tell you that the mode is equal to the average.

This leads you to C

HOWEVER, this information cannot be true because all numbers would be the mode if they were each separated by 3. So the true answer is E, but the information is not presented correctly.


Statement 1 intends to tell you that this is a consecutive set of multiples of 3 - NO.
The statement is "the difference between any two integers in the set is less than 3"
Because all the numbers are integers, then the positive difference between any two can be 0,1 or 2.

Originally posted by EvaJager on 20 Sep 2012, 11:01.
Last edited by EvaJager on 20 Sep 2012, 11:25, edited 1 time in total.
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Re: The mode of a set of integers is x. what is the difference [#permalink]
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St1:
Let set of integers be {x,x,x+1,x+2,x+2}
mode=x
median=x+1
diff=1
Another set of intergers {x-1,x,x,x,x+1}
mode=x
median=x
diff=0-----two diff values(Hence Insufficient)
St2:
Let set of integers be {x-5,x,x,x,x+5}
mode=x
median=x
diff=0
Another set of integers be {x-15,x,x,x+1,x+2,x+3,x+9}
mode=x
median=x+1
diff=1---two diff values(Hence Insufficient)

St1&St2:Let the set of integers be {x-1,x,x,x,x+1}
mode=x
median=x
diff=0
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Re: Mode - level:700-800 [#permalink]
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mneeti wrote:
The mode of a set of integers is x. What is the difference between the median of this set of integers and x?
(1) The difference between any two integers in the set is less than 3.
(2) The average of the set of integers is x.

The OA is C, but I do not get how. Please explain. Thanks !


1) Set could be (1,2,3,3), Difference = 3 - 2.25 = 0.75
or set could be (1,1,1), Difference = 1 - 1 = 0
Insufficient.

2)Set could be (-10,0,0,1,2,3,4), Difference = 1
or set could be (1,1,1), Difference = 1 - 1 = 0
Insufficient.

1 & 2 together Mean and mode are the same, so the mean has to be a number in the set. Also, the range cannot be more than 2. Hence only a set with the mode and the median being the same can satisfy such a condition. ie a set with the same number repeted in the middle with the highest and lowest being at the same distance from the middle number.

Sufficient. Answer is C. Although I doub whther I would have come up with this if i had not seen the OA. Would help if you could spoiler hide it.

Kudos Please... If my post helped.

Originally posted by MacFauz on 13 Nov 2012, 23:27.
Last edited by MacFauz on 14 Nov 2012, 04:40, edited 2 times in total.
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Re: Mode - level:700-800 [#permalink]
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MacFauz wrote:
mneeti wrote:
The mode of a set of integers is x. What is the difference between the median of this set of integers and x?
(1) The difference between any two integers in the set is less than 3.
(2) The average of the set of integers is x.

The OA is C, but I do not get how. Please explain. Thanks !


1) Set could be (1,2,3,3), Difference = 3 - 2.25 = 0.75or set could be (1,1,1), Difference = 1 - 1 = 0
Insufficient.

2)Set could be (-10,0,0,1,2,3,4), Difference = 1
or set could be (1,1,1), Difference = 1 - 1 = 0
Insufficient.

1 & 2 together Mean and mode are the same, so the mean has to be a number in the set. Also, the range cannot be more than 2. Hence only a set with the mode and the median being the same can satisfy such a condition. ie a set with the same number repeted in the middle with the highest and lowest being at the same distance from the middle number.

Sufficient. Answer is C. Although I doub whther I would have come up with this if i had not seen the OA. Would help if you could spoiler hide it.

Kudos Please... If my post helped.


Hii MacFauz...
I guess there is a typo in the red part. The median of a set consisting of even number of elements is the average of \((n/2) th term + {(n/2)+1} th term\).
So 2.25 must be 2.5.
Rest of the solution is just fantastic.

I went with an alternative approach.
1)The difference between any two integers in the set is less than 3. This can only happen in two cases.
i) When the set consists of same element.
ii) When the set consists of 3 consecutive integers. Note that when the set consists of only distinct integers, then all the integers are modes.
Two cases insufficient.
2) The average of the set of integers is x.
Not sufficient to answer the asked question.
On combining ,
either the set consists of same elements with the same number being the mode
OR
the set consists of consecutive elements. ex-{1,2,3}. In the given example, the modes are 1, 2 and 3. But as per the statement, the mode is x. What can be x?
Hence the previous case is considerd where the elements are same. Therefore difference would be 0.
C.
Hope that helps.

P.S. Please use spoiler to hide the OA.

Originally posted by Marcab on 14 Nov 2012, 00:08.
Last edited by Marcab on 14 Nov 2012, 00:12, edited 1 time in total.
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Re: Mode - level:700-800 [#permalink]
Marcab wrote:
MacFauz wrote:
mneeti wrote:
The mode of a set of integers is x. What is the difference between the median of this set of integers and x?
(1) The difference between any two integers in the set is less than 3.
(2) The average of the set of integers is x.

The OA is C, but I do not get how. Please explain. Thanks !


1) Set could be (1,2,3,3), Difference = 3 - 2.25 = 0.75or set could be (1,1,1), Difference = 1 - 1 = 0
Insufficient.

2)Set could be (-10,0,0,1,2,3,4), Difference = 1
or set could be (1,1,1), Difference = 1 - 1 = 0
Insufficient.

1 & 2 together Mean and mode are the same, so the mean has to be a number in the set. Also, the range cannot be more than 2. Hence only a set with the mode and the median being the same can satisfy such a condition. ie a set with the same number repeted in the middle with the highest and lowest being at the same distance from the middle number.

Sufficient. Answer is C. Although I doub whther I would have come up with this if i had not seen the OA. Would help if you could spoiler hide it.

Kudos Please... If my post helped.


Hii MacFauz...
I guess there is a typo in the red part. The median of a set consisting of even number of elements is the average of \(\frac{n}{2 th term + {(n/2)+1}th term}\).
So 2.25 must be 2.5.
Rest of the solution is just fantastic.

I went with an alternative approach.
1)The difference between any two integers in the set is less than 3. This can only happen in two cases.
i) When the set consists of same element.
ii) When the set consists of 3 consecutive integers. Note that when the set consists of only distinct integers, then all the integers are modes.
Two cases insufficient.
2) The average of the set of integers is x.
Not sufficient to answer the asked question.
On combining ,
either the set consists of same elements with the same number being the mode
OR
the set consists of consecutive elements. ex-{1,2,3}. In the given example, the modes are 1, 2 and 3. But as per the statement, the mode is x. What can be x?
Hence the previous case is considerd where the elements are same. Therefore difference would be 0.
C.
Hope that helps.

P.S. Please use spoiler to hide the OA.

Thanks Marcab... I've changed that now.. And it was not a typo.. I tend to make these silly mathematical mistakes :oops:
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Re: The mode of a set of integers is x. What is the difference [#permalink]
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1)The difference between any two integers in the set is less than 3. This can only happen in two cases.
i) When the set consists of same element.
ii) When the set consists of 3 consecutive integers. Note that when the set consists of only distinct integers, then all the integers are modes.
Two cases insufficient.
2) The average of the set of integers is x.
Not sufficient to answer the asked question.
On combining ,
either the set consists of same elements with the same number being the mode
OR
the set consists of consecutive elements. ex-{1,2,3}. In the given example, the modes are 1, 2 and 3. But as per the statement, the mode is x. What can be x?
Hence the previous case is considerd where the elements are same. Therefore difference would be 0.
C.
Hope that helps.
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Re: The mode of a set of integers is x. what is the difference [#permalink]
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hi,
Cant B be the answer??

We can use the relation

3 median=mode+2mean

directly.
Here, mode is given x (in the question).
And in the statement average (mean) is x.
So median is x
Difference = x-x=0.

Can
Quote:
Bunuel
or anybody please help????
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Re: The mode of a set of integers is x. what is the difference [#permalink]
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suramya26 wrote:
hi,
Cant B be the answer??

We can use the relation

3 median=mode+2mean
directly.
Here, mode is given x (in the question).
And in the statement average (mean) is x.
So median is x
Difference = x-x=0.

Can
Quote:
Bunuel
or anybody please help????


This is not exact formula, it's an approximation. You should not use it to get the exact value (I'd say not to use it altogether for the GMAT). Check the solutions above, they give examples of (2) being insufficient.
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Re: The mode of a set of integers is x. what is the difference [#permalink]
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Smita04 wrote:
The mode of a set of integers is x. what is the difference between the median of this set of integers and x?

(1) The difference between any two integers in the set is less than 3.
(2) The average of the set of integers s x.


Mode is the most frequent number. It could appear in the beginning, middle or end so has no connection to median, the middle number. We need to find a unique value for Median - x.

(1) The difference between any two integers in the set is less than 3.

So the integers would have a difference of 0/1/2.
They could be {1, 1, 2, 3} - median = 1.5 and x = 1
or {1, 2, 2, 3} - median = 2 and x = 2
etc
No unique value for median - x.

(2) The average of the set of integers is x.
Mode = x = Average
Since average is often somewhere in the middle, we could take some simple examples such as
Numbers could be {1, 2, 3, 3, 6} - median = 3 and x = 3
or {1, 2, 3, 4, 4, 10} - median = 3.5 and x = 4

Using both, we know that all we can have are at max three consecutive integers.
x is in the middle since it is the average. It also appears maximum number of times. So if x = 5, other integers can only be 4 and/or 6. Since 5 is the average too, if there is a 4, there must be a 6 too. For every 4, there should be a 6 to make up the deficit. So something like this is possible
{4, 4, 5, 5, 5, 6, 6}
or
{4, 5, 5,5 ,5 ,5 ,5 6}
or
{4, 4, 4,4, 5, 5, 5, 5, 5, 6, 6, 6, 6}

Since x is the mode too, it will outnumber 4s and 6s. So the middle value will always be x only. Difference between median and x will be 0.
Answer (C)
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Re: The mode of a set of integers is x. what is the difference [#permalink]
Bunuel wrote:
suramya26 wrote:
hi,
Cant B be the answer??

We can use the relation

3 median=mode+2mean
directly.
Here, mode is given x (in the question).
And in the statement average (mean) is x.
So median is x
Difference = x-x=0.

Can
Quote:
Bunuel
or anybody please help????


This is not exact formula, it's an approximation. You should not use it to get the exact value (I'd say not to use it altogether for the GMAT). Check the solutions above, they give examples of (2) being insufficient.



Bunuel, please explain how this empirical relationship between mean, median and mode is considered as approximation ?

Posted from my mobile device
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The mode of a set of integers is x. what is the difference [#permalink]
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Adityapradhan740 wrote:
Bunuel, please explain how this empirical relationship between mean, median and mode is considered as approximation ?

Posted from my mobile device


Since you haven't tagged Bunuel he may not see this thread so I am replying here.

3 median=mode+2mean is an empirical formula - observed relation. It is not theoretically established. It is an approximation that works in cases of moderately skewed distribution. In a symmetric normal distribution, mean = mode = median

If one or two data points are far away from the median, the relation fails. The mean could take a value far away from the median.

Example 1: 1, 2, 2, 3, 4, 6, 8
Median = 3
Mode = 2
Mean = 3.7

3*3 = 2 + 2*3.7 (approximately)

Example 2: 1, 2, 2, 3, 4, 6, 100
Median = 3
Mode = 2
Mean = 16.8

Relation breaks. Hence ignore the relation.
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