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Re: A box contains four coins, of which two coins have heads on [#permalink]
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How many ways can you get heads with a two-headed coin? There are four ways (2 heads in one two-headed coin and 2 heads in the other two-headed coin)

How many ways can you get heads from this entire set of coins? There are five ways (four as identified above and one from the normal coin)

Therefore probability = 4/5

Option C
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Re: A box contains four coins, of which two coins have heads on [#permalink]
I would say
There are total 4 coins of which only 2 coins have both heads, so the answer is 2/4 = 1/2.
Not sure whether each head can be treated separately...

Posted from my mobile device
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Re: A box contains four coins, of which two coins have heads on [#permalink]
GyanOne wrote:
How many ways can you get heads with a two-headed coin? There are four ways (2 heads in one two-headed coin and 2 heads in the other two-headed coin)

How many ways can you get heads from this entire set of coins? There are five ways (four as identified above and one from the normal coin)

Therefore probability = 4/5

Option C


Can you please explain this -
If I have already tossed the coin and have got a head then how is the probability of getting another head on the other face = 4/5 ??
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Re: A box contains four coins, of which two coins have heads on [#permalink]
pariearth wrote:
A box contains four coins, of which two coins have heads on both their faces, one coin has tail on both its faces and the fourth coin is a normal one. A coin is picked at random and then tossed. If head is the outcome of the toss, then find the probability that the other face(hidden face) of the coin tossed is also a head.
A. 2/5
B. 1/2
C. 4/5
D. 2/3
E. 3/4

Guys need a detailed explaination here..


If head comes out of toss, then the coin is among: two coins that have heads on both their faces and the normal one.

Total possible outcomes: 3 (HHT)
Possible head : 2 (ruling out the tail for the normal coin)

Probability = 2/3
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Re: A box contains four coins, of which two coins have heads on [#permalink]
Thank you gyanOne.

What is the source of this question?
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Re: A box contains four coins, of which two coins have heads on [#permalink]
nt2010 wrote:
What is the source of this question?


This is from my not-so-famous tution class' study material.
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Re: A box contains four coins, of which two coins have heads on [#permalink]
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@pariearth.....you are certainly welcome. Do let us know if you face any further difficulty in understanding this concept. The important part of a probability problem is always setting it up by first understanding what is being asked.
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Re: A box contains four coins, of which two coins have heads on [#permalink]
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pariearth wrote:
A box contains four coins, of which two coins have heads on both their faces, one coin has tail on both its faces and the fourth coin is a normal one. A coin is picked at random and then tossed. If head is the outcome of the toss, then find the probability that the other face (hidden face) of the coin tossed is also a head.

A. 2/5
B. 1/2
C. 4/5
D. 2/3
E. 3/4


More questions on conditional probability to practice:
if-ben-were-to-lose-the-championship-m07q12-75695.html
given-a-bag-with-2-black-balls-and-3-white-balls-126223.html
say-you-have-5-coins-1-coin-has-heads-on-both-sides-and-the-91232.html

Hope it helps.
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Re: A box contains four coins, of which two coins have heads on [#permalink]
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Hi All,

This question can be approached with a bit of 'brute force' math - you just have to write everything down and stay organized. To start, I'm going to refer to 8 faces on the 4 coins as:

H1/H2
H3/H4
H5/T1
T2/T3

Based on the information in the prompt, we know that 5 of the 8 'faces' are heads, so if we randomly pick a coin and flip 'heads', then one of the first 3 coins MUST have been chosen (since the 4th coin has two 'tails', it could not ever flip 'heads').

From there, we're asked for the probability that the other side of the coin is also 'heads.' With a 'heads' face-up, here are the following possible outcomes:
H1 up/H2 down
H2 up/H1 down
H3 up/H4 down
H4 up/H3 down
H5 up/T1 down

4 of the 5 'heads up' options have a 'head' on the other side.

Final Answer:

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Re: A box contains four coins, of which two coins have heads on [#permalink]
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pariearth wrote:
A box contains four coins, of which two coins have heads on both their faces, one coin has tail on both its faces and the fourth coin is a normal one. A coin is picked at random and then tossed. If head is the outcome of the toss, then find the probability that the other face (hidden face) of the coin tossed is also a head.

A. 2/5
B. 1/2
C. 4/5
D. 2/3
E. 3/4


Since there are only 3 coins that have a head on at least one face and the outcome of the toss is a head, we can ignore the coin with tails on both faces. Now, let’s label the faces of the other 3 coins.

One of coins with both heads: H1, H2

The other coin with both heads: H3, H4

The coin with one head and one tail: H5, T1

Since the outcome of the toss is a head, it’s possible is from one of the following (shown face / hidden face):

H1 / H2

H2 / H1

H3 / H4

H4 / H3

H5 / T1

We see that from the 5 outcomes above where the shown face is a head, 4 of them have a head on the hidden face also. Therefore, the probability that the hidden face of the coin tossed is also a head is 4/5.

Answer: C
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Re: A box contains four coins, of which two coins have heads on [#permalink]
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