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If x/y = 2/3, then (x - y)/x?

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njss750
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If x/y = 2/3, then (x - y)/x? [#permalink] New post   21 Oct 2005, 01:42
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If \(\frac{x}{y} = \frac{2}{3}\), then \(\frac{x - y}{x}\)?

A. -1/2
B. -1/3
C. 1/3
D. 1/2
E. 5/2
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Bunuel
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Re: If x/y = 2/3, then (x - y)/x? [#permalink] New post   17 Sep 2013, 19:17
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njss750 wrote:
If x/y =2/3, then (x-y)/x?

A. -1/2
B. -1/3
C. 1/3
D. 1/2
E. 5/2


x/y=2/3 --> y/x=3/2.

\(\frac{x-y}{x}=1-\frac{y}{x}=1-\frac{3}{2}=-\frac{1}{2}\).

Answer: A.
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Re: If x/y = 2/3, then (x - y)/x? [#permalink] New post   21 Nov 2013, 21:32
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sdlucas wrote:
I'm still confused. Where does the 1 come from?


You separate out the numerator.

\(\frac{(x-y)}{x} = \frac{x}{x} - \frac{y}{x} = 1 - \frac{y}{x} = 1 - \frac{3}{2} = -\frac{1}{2}\)
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Re: If x/y = 2/3, then (x - y)/x? [#permalink] New post   21 Nov 2013, 19:59
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I'm still confused. Where does the 1 come from?
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Re: If x/y = 2/3, then (x - y)/x? [#permalink] New post   19 Apr 2016, 16:12
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did i get lucky? or can this be a correct approach.

I cross multiplied to get 3x=2y. I then divided by 3 to get 2/3y and just plugged that into where ever x was
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Re: If x/y = 2/3, then (x - y)/x? [#permalink] New post   19 Apr 2016, 22:12
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ross14 wrote:
did i get lucky? or can this be a correct approach.

I cross multiplied to get 3x=2y. I then divided by 3 to get 2/3y and just plugged that into where ever x was


Yes, the approach is fine. You are eliminating one variable, bringing it all in terms of a single variable and then cancelling it off to get a value.
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Re: If x/y = 2/3, then (x - y)/x? [#permalink] New post   29 Oct 2017, 11:15
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njss750 wrote:
If x/y =2/3, then (x-y)/x?

A. -1/2
B. -1/3
C. 1/3
D. 1/2
E. 5/2


Replace x = 2 & y = 3

So, \(\frac{(x-y)}{x} = \frac{2 - 3}{2} = -\frac{1}{2}\)

Hence, answer will be (A) \(-\frac{1}{2}\)
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Re: If x/y = 2/3, then (x - y)/x? [#permalink] New post   01 Jan 2020, 19:43
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njss750 wrote:
If \(\frac{x}{y} = \frac{2}{3}\), then \(\frac{x - y}{x}\)?

A. -1/2
B. -1/3
C. 1/3
D. 1/2
E. 5/2


Cross-multiplying, we have:

3X = 2Y

Thus, we can let X = 2 and Y = 3, so we have:

(2 - 3)/2 = -1/2

Alternate Solution:

(X-Y)/X = X/X - Y/X = 1 - Y/X

Since X/Y = 2/3, Y/X = 3/2, so 1 - Y/X = 1 - 3/2 = -1/2.

Answer: A
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Re: If x/y = 2/3, then (x - y)/x? [#permalink] New post   01 Apr 2023, 02:46
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Re: If x/y = 2/3, then (x - y)/x? [#permalink]
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