RMD007 wrote:
Bunuel, please help in this question. I am unable to get the question stem.
Does it not mean we just have 6 tokens with 1-6 written on it without duplicates?
Yes, it means that there are 6 tokens numbered from 1 to 6, inclusive: [1]; [2]; [3]; [4]; [5]; [6].
A bag contains six tokens, each labeled with one of the integers from 1 to 6, inclusive. Each integer appears on one token. When three tokens are removed at random, without replacement, what is the probability that the sum of numbers on those three tokens is equal to the positive integer N?Notice several things:
1. We are picking without replacement, so if we pick [1] there won't be any more [1]'s left in the bag.
2. The least possible sum (N) is 1 + 2 + 3 = 6 and the greatest possible sum is 6 + 5 + 4 = 15.
3. The sums from 6 to 15 has different ways (combinations) to occur. For example, we can get 6 only in one way: 1 + 2 + 3 = 6 but we can get 8 in 2 ways: 1 + 2 + 5 = 1 + 3 + 4 = 8.
4.We can get the number of combinations for each sum, thus we can get the total number of combinations for all sums.
(1) There is only one combination of three tokens in the bag that sums to N. There are many value of N possible for example, if N = 1, then the probability is 0 (you cannot get the sum of 1 by adding three positive integers). But if say N = 6 (we can get 6 in one way: 6 = 1 + 2 + 3 only), then the probability is not 0 (it does not matter what it's actually is). Not sufficient.
(2) N is a multiple of 7. The greatest sum is 6 + 5 + 4 = 15, so for N to be a multiple of 7 it must be 7 or 14. Both of these numbers can be broken into the sum of three distinct positive integers only in one way: 7 = 1 + 2 + 4 and 14 = 6 + 5 + 3. Sufficient.
Answer: B.
Hope it helps.