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The average (arithmetic mean) of 6 numbers is 8.5. When one

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Bunuel
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The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  07 Feb 2014, 05:48
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The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0
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Bunuel
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  07 Feb 2014, 05:48
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SOLUTION

The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0

The average of 6 numbers is 8.5 --> the sum of 6 numbers = (mean)*(number of terms) = 8.5*6 = 51.

The average of 5 numbers is 7.2 --> the sum of 5 numbers = (mean)*(number of terms) = 7.2*5 = 36.

The discarded number = 51 - 36 = 15.

Answer: E.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  17 Dec 2017, 10:02
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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0


Average of 6 numbers = (sum of all 6 numbers)/6
We get: 8.5 = (sum of all 6 numbers)/6
So, sum of the 6 numbers = (6)(8.5)
= 51

When one number is discarded, the average of the remaining numbers becomes 7.2
Sum of remaining 5 numbers = (5)(7.2)
= 36

Discarded number = (sum of original 6 numbers) - (sum of remaining 5 numbers)
= 51 - 36
= 15
= E

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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  07 Feb 2014, 11:10
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The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2 .What is the discarded number?


Sol: Since avg is given for 6 nos, we can find the sum total which is 8.5*6= 51

New average after removal of one number is 7.2 so sum total of 5 nos is 36

Discarded number is 51-36=15

Ans E

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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  07 Feb 2014, 13:06
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Given that the average of 6 numbers is 8.5, then the sum of these numbers is 6*8.5= 51.

Let 'x' be the number removed, (51-x)/5 = 7.2. Solving for x, we get x = 15, so (E).
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  21 Feb 2016, 12:48
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Let's assume every number was 8.5 in the original set, now in order to reduce average to 7.2 by removing just one number, 1.3 \((8.5-7.2=1.3)\) needs to be subtracted from remaining 5 numbers \((1.3*5=6.5)\) along with removing one of the original numbers, i.e. \(6.5+8.5=15.0\)
Answer: E
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  09 Dec 2016, 02:19
Here is my solution to this one-->

Sum(1)=6*8.5=>51
Sum(2)=5*7.2=>36
Hence the discarded number must be 51-36=15

Hence E
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  10 Dec 2016, 01:32
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Bunuel wrote:
The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0


\(8.5*6 - x = 7.2*5\)

Or, \(51 - x = 36\)

Or, \(x = 15\)

Hence, answer will be (E) 15
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  10 Mar 2017, 23:41
this can be solved very easily from the following method
N-7.2/6 +7.2=8.5 so the new no. will be after solving for N=15
so the answer is E
after knowing the S.D. very precisely we gonna solve these questions within 30 sec.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  11 Mar 2017, 00:16
Bunuel wrote:
The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0


\(8.5*6 - X = 7.2*5\)

\(51 - x = 36\)

Or, \(x = 15\)

Thus, the discarded number will be (E) 15.00
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  26 Nov 2019, 19:37
Quote:

The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0


(8.5*6)-(7.2*5)=51-36=15. Option E.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  21 Apr 2020, 06:55
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8.5*6= 51

7.2*5= 36

51-36=15

Answer is E.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  06 Aug 2022, 00:05
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Theory

    ➡ Average = Sum of all the Values / Total Number of Values
    ➡ Sum of all the Values = Average * Total Number of Values

The average (arithmetic mean) of 6 numbers is 8.5

Sum of 6 numbers = Average * 6 = 8.5 * 6 = 51

When one number is discarded, the average of the remaining numbers becomes 7.2

Sum of remaining 5 numbers = Average * 5 = 7.2 * 5 = 36

Discarded number = Sum of 6 numbers - Sum of remaining 5 numbers = 51 - 36 = 15

So, Answer will be E.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink] New post  28 May 2023, 14:32
Let's denote the discarded number as x.

The average of 6 numbers is given as 8.5, so the sum of these 6 numbers is 6 * 8.5 = 51.

When the number x is discarded, the average of the remaining 5 numbers becomes 7.2. So, the sum of the remaining 5 numbers is 5 * 7.2 = 36.

To find the discarded number x, we can subtract the sum of the remaining 5 numbers from the sum of the original 6 numbers:

51 - 36 = 15

Therefore, the discarded number is 15.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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