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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
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Hi ,

This is how i approached the solution :

Bananas harvested in 2001 = 1.5 X
Bananas harvested in 2002 = 4X

Percentage growth = ((4X - 1.5X)/1.5X) * 100 = 166.67% = 167% (B)

Hope this helps.
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
Thats the second way I did it but how did you find it so accurately without using a calculator?

So this is the way I did it. The least complicated way like yours but slightly different. Please let me know if this is wrong.

2000 = X
2001 = 1.5 x
2002 = 4x

SO New value - Old value / old value =

4x - 1.5x / 1.5x = 2.5x / 1.5x = 5/3 (in fraction form) reduced from 25/15

1/3 = 0.33333

so 5 * 0.3333 = 0.16665 * 100 = 166.65 = 167% :)

or if you know 3/3 is a whole 100 % then 2/3 = .666666 continuous * 100 = 66.66

and added together 166.67 --> 167%
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
If bananas harvested in 2000 was X (100) then surely a 150% growth of X (100) would mean bananas harvested in 2001 of 2.5X (250)

Going from 1X to 1.5X would be equivalent of 50% growth (as opposed to 150)?

I think the answer is A
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
jasdhanda wrote:
Thats the second way I did it but how did you find it so accurately without using a calculator?

So this is the way I did it. The least complicated way like yours but slightly different. Please let me know if this is wrong.

2000 = X
2001 = 1.5 x
2002 = 4x

SO New value - Old value / old value =

4x - 1.5x / 1.5x = 2.5x / 1.5x = 5/3 (in fraction form) reduced from 25/15

1/3 = 0.33333

so 5 * 0.3333 = 0.16665 * 100 = 166.65 = 167% :)

or if you know 3/3 is a whole 100 % then 2/3 = .666666 continuous * 100 = 66.66

and added together 166.67 --> 167%


Hi ,

You were correct till this step : 4x - 1.5x / 1.5x = 2.5x / 1.5x = 5/3 (in fraction form) reduced from 25/15

But then to find 5/3, you do not need to do 1/3 * 5 . Just simply do a long division of 5 by 3. You will get 1.66666..... Now to convert this decimal to percent, shift the decimal 2 places to the right and you get 166.66.. The closest option in the answers is 167%.
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
phferr1984 wrote:
If bananas harvested in 2000 was X (100) then surely a 150% growth of X (100) would mean bananas harvested in 2001 of 2.5X (250)

Going from 1X to 1.5X would be equivalent of 50% growth (as opposed to 150)?

I think the answer is A



Hi,

A growth of 150 % means 1.5 * X and not 2.5 * X.

For e.g : Lets say the number of bananas in 2000 = 100
Then number of bananas in 2001 = 150 % of 100 ; which means add 50 % of 100 to itself = 100 + 50 = 150.
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
[quote="saket2160"


Hi,

A growth of 150 % means 1.5 * X and not 2.5 * X.

For e.g : Lets say the number of bananas in 2000 = 100
Then number of bananas in 2001 = 150 % of 100 ; which means add 50 % of 100 to itself = 100 + 50 = 150.[/quote]

So if there were 100 bananas harvested in 2001 and the harvest grew BY 50% - how many bananas would be harvested? How can 50% growth be the same as 150% growth?

If I have a stock portfolio (100) and it grew by 9% in one year - it would be worth 109 at the end of the year?

I'm struggling with this one...
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
I agree A.

2000: x
2001: 2.5x
2002: 5x

(5x/2.5x) - 1 = Y%/100
Y%=100
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
jasdhanda wrote:
The number of bananas harvested in 2000 was the integer x. In 2001, the number of bananas harvested grew by 150% from the year 2000. In 2002, the number of bananas harvested grew by 400% from the year 2000. What was the percentage growth in the number of bananas harvested from the year 2001 to the year 2002?

(A) 100%
(B) 167%
(C) 200%
(D) 250%
(E) 500%



Year 2000 = x

Year 2001 \(= x + \frac{150x}{100}= \frac{250x}{100}\)

Year 2002 \(= x +\frac{400x}{100}= \frac{500x}{100}\)

Percentage growth from the year 2001 to the year 2002

\(= \frac{\frac{500x}{100} - \frac{250x}{100}}{\frac{250x}{100}} * 100\)

= 100

Answer = A = 100%

Bunuel, can you kindly confirm the answer ?
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
jasdhanda,phferr1984,

Apologies from my end. I made a mistake in considering the increase in the percentages as they were above 100%. Option A would be the correct answer.
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
saket2160 wrote:
jasdhanda,phferr1984,

Apologies from my end. I made a mistake in considering the increase in the percentages as they were above 100%. Option A would be the correct answer.


After going through the thread it feels like the real confusion was that did the harvest increased by the given % or became equal to.

I believe the question means increased by the given %.

Hence, the answer is A

2001 = x+1.5X
2002 = x+4X

so the % increase is 2.5x/2.5x *100 = 100%

-------------------
Kudos if the answer helped :)
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
We get x, 2.5x, 5x. So, 5x/2.5x=2 times means 100%
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
We get x, 2.5x, 5x. So, 5x/2.5x=2 times means 100%. Picking gives 100, 250, 500, and 500/250=2 times (100%)
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Percent change [#permalink]
The number of bananas harvested in 2000 was the integer x. In 2001 the number of bananas harvested grew by 150% from the year 2000. In 2002 the number of bananas harvested grew by 400% from the year 2000. What was the percentage growth in the number of bananas harvested from the year 2001 to the year 2002?

a) 100%
b) 167%
c) 200%
d) 250%
e) 500%
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
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sabrina3509 wrote:
The number of bananas harvested in 2000 was the integer x. In 2001 the number of bananas harvested grew by 150% from the year 2000. In 2002 the number of bananas harvested grew by 400% from the year 2000. What was the percentage growth in the number of bananas harvested from the year 2001 to the year 2002?

a) 100%
b) 167%
c) 200%
d) 250%
e) 500%


Merging topics. Please refer to the discussion above.

Also, please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Thank you.
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
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sabrina3509 wrote:
The number of bananas harvested in 2000 was the integer x. In 2001 the number of bananas harvested grew by 150% from the year 2000. In 2002 the number of bananas harvested grew by 400% from the year 2000. What was the percentage growth in the number of bananas harvested from the year 2001 to the year 2002?

a) 100%
b) 167%
c) 200%
d) 250%
e) 500%


Year - Bananas
2000 - x
2001 - x + 1.5x = 2.5x
2002 - x + 4x = 5x

Percentage growth from 2001 to 2002 = (5 - 2.5) / 2.5*100 = 100%

Correct Option: A
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
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The number of bananas harvested in 2000 was the integer x. In 2001, the number of bananas harvested grew by 150% from the year 2000. In 2002, the number of bananas harvested grew by 400% from the year 2000. What was the percentage growth in the number of bananas harvested from the year 2001 to the year 2002?

Lets use plugin values to solve this question.

Assume that no of bananas in the year 2000 = 100

In 2001, the number of bananas harvested grew by 150% from the year 2000.

No of bananas in the year 2001 = 100 + 150 % of 100 = 100 + 150 = 250.

In 2002, the number of bananas harvested grew by 400% from the year 2000.

No of bananas in the year 2002 = 100 + 400 % of 100 = 100 + 400 = 500.

Percentage increase in the no of bananas from the year 2001 to 2002 i.e from 250 to 500 = 250/250 * 100 = 100 %

Option A is the answer.

Thanks,
Clifin J Francis,
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Re: The number of bananas harvested in 2000 was the integer x. I [#permalink]
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