One hour after Yolanda started walking from X to Y, a distan

When bob starts walking The distance between them is 45-3 = 42 miles
If they meet at time t then Yolanda would have walked
X/3 minutes and Bob would have walked (42-X)/4 mins
X/3 = (42-X)/4 so X = 18
Bob would have walked 42-18 = 24 miles.

When bob starts walking The distance left between them is 45-3 = 42 miles

Time taken to meet = Distance / Relative speed
= 42/(3+4) = 6 hours

so, bob walked = 6 x 4 = 24 miles
Ans. A.

3+3t+4t=45
t=6
Bob==>4*6=24
==>A

Let say they meet after x hrs.

so 3x + 4 (x-1) = 45 "As Bob started after an hour"

after solving the above equation we get answer as 24

Yolanda has already covered 3 kms out of 45

So remaining distance = 42

Time taken by both to meet at a point will be the same in the stretch of 42 kms

Bob travels distance = x
Speed = 4

Yolaondu will travel = 42 - x
Speed = 3

\(\frac{x}{4} = \frac{42-x}{3}\)

x = 24 = Answer = A

Let t be the number of hours that Bob had walked when he met Yolanda. Then, when they met, Bob had walked 4t miles and Yolanda had walked 3(t + 1) miles. These distances must sum to 45 miles, so 4t + 3(t + 1) = 45, which may be solved for t as follows
4t + 3(t + 1) = 45
4t + 3t + 3 = 45
7t = 42
T = 6 (hours)
Therefore, Bob had walked 4t = 4(6) = 24 miles when they met. The best answer is A.

This can be solved using the "Relative speed approach" as well. The advantage is that we can solve mentally.

Let's first talk about the concept of relative speed:

When two objects travel in the same direction, the relative speed of one with respect to another is the difference between the individual speeds.

And when two objects travel in the opposite direction, the relative speed is the sum of the individual speeds.

In this case, Yolanda’s<hereforth referred as Y> has a lead time of 1 hour. So distance already traveled by Y=3 miles.

Remaining distance to be covered when both Y and B move = 45-3=42.

This distance is covered at the net speed of \(3(Y's speed)+4(B's speed)= 7 mph (Opp direction)\)

So time taken by both to meet = \(\frac{42}{7} = 6\)

Distance traveled by B in 6 hours = \(6*4=24 miles\)

Since the speed of both are 3 and 4 , the end answer must be a multiple of both . Only 24 is present in that case.

This method might help in the worst case.

can someone tell me what I am missing please. I read the explanations, and still am not getting it. Why isn't it 12miles (i Know not an option)

Y=3 after 1st hour, 6 after 2 hours, 9 after 3 hours, 12 after 4 hours.
bob=4 after one, 8 after 2 ect

y has a 3 mile head start so..

y=3, B=0
y=6, b=4
y=9, B=8
y=12, b=12??

please explain. Thank you

The distance between X and Y is 45 miles so the combined distance covered also must be 45 miles.

y=3, B=0
y=6, b=4
y=9, B=8
y=12, b=12
y=15, b=16
y=18, b=20
y=21, b=24 --> 21 + 24 = 45.

Hope it's clear.

1. In 1 hr Yolanda would have walked 3 miles
2. Yolanda and Bob both walk simultaneously after that and move towards each other.
3. They would have met after (45-3)/(3+4)= 6hrs
4. In 6 hrs, Bob would have walked , 6*4=24 miles

Distance=45 miles

Yolanda's speed=3 miles/hr Bob's speed=4 miles/hr

Distance between them when Bob starts=42 (as Yolanda has covered a distance of 3 miles)

The time they will meet = 42/(3+4) miles/hr=6 hr

Miles Bob walked when they met= 4 miles/hr *6 hr=24 miles

A

Yolanda has already covered 3 miles in one hour.

Out of 45miles, distance left to cover = 45-3 =42 miles

The relative speed = 3+4=7 miles/hr

Time to cover it = 42/7 =6 hour.

In 6 hours, B @4mph would have walked 6 * 4 = 24miles.

(option a)

D.S
GMAT SME

let be the time taken x be the distance from X

t=x/3 , t-1 = 45-x/4
=>x/3+x-45/4 = 1
=>x=21

we want from Y 45-21 = 24
therefore IMO A

Welcome to the challenging and exciting world of GMAT Focus Edition. I'm Claudio Hurtado, your expert guide to GMAT Focus Edition in the Quantitative Reasoning section, here to take you through a journey full of discoveries and problem solving.
Imagine this scene: Yolanda embarks on a journey from point X to Y, while Bob begins his walk in the opposite direction, from Y to X, an hour later. The distance between them covers 45 miles. Yolanda walks at a steady pace of 3 miles per hour, while Bob walks at a brisk pace of 4 miles per hour. The question that arises is: how many miles had Bob walked when they finally met?

This is the time to apply our problem-solving skills. We must carefully analyze the situation and develop a strategy to discover the answer.

Let's see it step by step. Suppose t represents the number of hours Bob had walked when he met Yolanda. At that time, Bob had traveled 4t miles, while Yolanda, having walked for an hour more, had traveled 3(t + 1) miles. Together, their distances should add up to a total distance of 45 miles.
Now, armed with this equation, we embark on our search for the solution:

4t + 3(t + 1) = 45

Expanding and simplifying, we find:

7t + 3 = 45

7t = 42

Solving for t, we find that t is equal to 6 hours. Therefore, when they met, Bob had traveled 4t miles, which is equivalent to 4 multiplied by 6, resulting in 24 miles.

Confidently, we concluded that Bob had walked 24 miles when they crossed paths. The right answer? A resounding option A.

This problem serves as a testament to the power of analytical thinking and strategic problem-solving techniques. With Claudio Hurtado (+56 945 517 215) as your trusted guide, you'll navigate the complexities of the GMAT Focus Edition with ease, unlocking doors to success, one problem at a time.
So, equip yourself with determination and embark on this exciting journey with me. Together, we will conquer the Quantitative Reasoning section of the GMAT Focus Edition and emerge victorious.

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