Bunuel wrote:
If \(m\) and \(n\) are positive integers, is the remainder of \(\frac{10^m + n}{3}\) greater than the remainder of \(\frac{10^n + m}{3}\)?
(1) \(m \gt n\)
(2) The remainder of \(\frac{n}{3}\) is \(2\)
Target question: Is the remainder of \(\frac{10^m + n}{3}\) greater than the remainder of \(\frac{10^n + m}{3}\)? Statement 1: \(m \gt n\) This statement doesn't feel sufficient, so I'll TEST some values.
There are several values of m and n that satisfy statement 1. Here are two:
Case a: m = 2 and n = 1. \(10^m + n=10^2 + 1=101\), and 101 divided by 3 leaves a remainder of
2. Similarly, \(10^n + m=10^1 + 2=12\), and 12 divided by 3 leaves a remainder of
0. So, in this case, the answer to the target question is
YESCase b: m = 3 and n = 2. \(10^m + n=10^3 + 2=1002\), and 1002 divided by 3 leaves a remainder of
0. Similarly, \(10^n + m=10^2 + 3=103\), and 103 divided by 3 leaves a remainder of
1. So, in this case, the answer to the target question is
NOSince we can’t answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: The remainder of \(\frac{n}{3}\) is \(2\)In other words,
n is 2 greater than some of multiple of 3In other words,
n = 3k + 2 for some integer k
We must also recognize that when we divide \(10^m - 1\) by 3, the remainder will always be 0 (as long as b is a positive integer)
We know this because \(10^m - 1\) will always result in an integer that consists solely of 9's.
For example, \(10^2 - 1=99\) and \(10^4 - 1=9999\) etc.
The divisibility rule for 3 tells us that any number consisting solely of 9's will be divisible by 3.
If \(10^m - 1\) is divisible by 3, then \(10^m\) is
1 greater than a multiple of 3In other words
\(10^m\) = 3j + 1 for some integer j.
At this point, we can see that \(10^m + n = (3j + 1) + (3k + 2)=3j+3k+3=3(j+k+1)\)
Since we can be certain that \(3(j+k+1)\) is a multiple of 3, we know that 3(j+k+1) divided by 3 must leave a remainder of
0Since
0 is the smallest possible remainder, we can be certain that
the remainder of \(\frac{10^m + n}{3}\) is NOT greater than the remainder of \(\frac{10^n + m}{3}\)
Since we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: B
Cheers,
Brent