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Re: M23-24 [#permalink]
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I think this is a high-quality question and I don't agree with the explanation. When we solve wstatement-1, we will get 2 values either (l,b) = (40,2) or (2,40), so accordingly angle will also be different. So, not sufficient. Answer must be option B. Kindly correct if I am wrong.
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Re: M23-24 [#permalink]
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mohitpoddar wrote:
I think this is a high-quality question and I don't agree with the explanation. When we solve wstatement-1, we will get 2 values either (l,b) = (40,2) or (2,40), so accordingly angle will also be different. So, not sufficient. Answer must be option B. Kindly correct if I am wrong.


We need to find the angle between the diagonal of the rectangle and its longer side. So, it does not matter whether it's (40,2) or (2,40). In any case we should find the angle between the diagonal and the side of length 40.
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Re: M23-24 [#permalink]
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I like this Magoosh explanation in regards to determining the uniqueness of a triangle. In short, if we can determine unique values for SAS, SSS, and etc (see link for full list), then we can determine everything about a triangle since we are essentially breaking the problem down into two triangles.

https://magoosh.com/gmat/2012/gmat-data ... nce-rules/
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Re: M23-24 [#permalink]
Hi Bunuel chetan2u GMATinsight ,

I am way too confused with this one . Two doubts :

1. width and length can be some irrational or a rational (nowhere stated that the length or the width has to be an integer) , and can lead to area 80 and perimeter 84. We can't uniquely define the angle between the longer side and diagnol

2. for option B, we can make two diagrams

one--- with length as 2 and width as 40 ,,,, so the diagnol will make some angle with the width
two--- with width as 2 and length as 40 ,,,, so the diagnol will make some angle with the length

and in both the above cases we ll have a different angle to look for unless rectangle is a square, which is not the case here.

Please help :)
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Re: M23-24 [#permalink]
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ShankSouljaBoi wrote:
Hi Bunuel chetan2u GMATinsight ,

I am way too confused with this one . Two doubts :

1. width and length can be some irrational or a rational (nowhere stated that the length or the width has to be an integer) , and can lead to area 80 and perimeter 84. We can't uniquely define the angle between the longer side and diagnol

2. for option B, we can make two diagrams

one--- with length as 2 and width as 40 ,,,, so the diagnol will make some angle with the width
two--- with width as 2 and length as 40 ,,,, so the diagnol will make some angle with the length

and in both the above cases we ll have a different angle to look for unless rectangle is a square, which is not the case here.

Please help :)

If the area of a rectangle is 80, what is the angle between the diagonal of the rectangle and its longer side?


(1) The perimeter of the rectangle is 84

(2) The shorter side of the rectangle is 2


Area = l*b = 84

STatement 1: Perimeter, l+b = 84/2 = 42

i.e. We get a quadratic equation to get two values of l

but one of them will be l and other will be b so Unique Solution hence

SUFFICIENT

Statement 2: Shorter side = 2

i.e. b = 2 if l > b

i.e. l = 80/2 = 40

there will be a unique rectangle with sides 2 and 40 hence

SUFFICIENT

Answer: Option D

ShankSouljaBoi please make two figures and post here for statement B which are bothering you. :)
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M23-24 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M23-24 [#permalink]
Hi Bunuel,
Just out of curiosity, How do you calculate the Angles in the given case.

Thanks in advance :)
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Re: M23-24 [#permalink]
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umangshah wrote:
Hi Bunuel,
Just out of curiosity, How do you calculate the Angles in the given case.

Thanks in advance :)


Figuring out angles in right triangles that aren't the usual 30-60-90 or 45-45-90 types is not something you need to know for the GMAT.
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Re: M23-24 [#permalink]
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