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Re: Is J + K > L + M ? [#permalink]
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nelo5390 wrote:
But what makes E correct, and why not C?


Is J + K > L + M ?

(1) J > L + M. If J = K = 1 and L + M = 0, then J + K > L + M but if If J = 1, K = -1 and L + M = 0, then J + K = L + M. Not sufficient.

(2) K > L + M. If J = K = 1 and L + M = 0, then J + K > L + M but if If J = -1, K = 1 and L + M = 0, then J + K = L + M. Not sufficient.

(1)+(2):

If J = K = 1 and L + M = 0, then J + K > L + M
If J = K = -1 and L + M = -2, then J + K = L + M.

Not sufficient.

Answer: E.
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Re: Is J + K > L + M ? [#permalink]
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gmatquant25 wrote:
Is J + K > L + M ?

(1) J > L + M

(2) K > L + M


we can clearly see 1 and 2 alone are insufficient.

(1)+(2)

assume all terms are +ve
add the inequality
(j+k) > 2(l+m)

assume all terms are -ve
add the inequality
(j+k) < 2(l+m)

so E. :)
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Re: Is J + K > L + M ? [#permalink]
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