DropBear wrote:
VeritasPrepKarishma wrote:
reto wrote:
What is the minimum number of randomly chosen people needed in order to have a better-than-50% chance that at least one of them was born in a leap year?
A. 1
B. 2
C. 3
D. 4
E. 5
Keeping it simple:
P (A person was born in leap year) = 1/4
This is less than 50% - not the answer
I understand and follow this partP (A or B was born in a leap year) = P (A born in leap year) + P (B born in leap year) - P (Both born in leap year)
Because we are looking for "at least one" shouldn't we be trying to determine P(A, or B, or Both) born in a leap year? I had the same answer as you and had the correct answer but probabilities are a bit of a weakness of mine so trying to work on it. I will show below my working.The two events are independent. Probability that A was born is a leap year is independent of the probability that B was born in a leap year.
So P(Both) = P(A)*P(B)
P (A or B was born in a leap year) = 1/4 + 1/4 - (1/4)*(1/4) = 1/2 - 1/16
This is less than 50% but close - not the answer
So when you pick, three people, the probability of someone born in a leap year will be higher than 50%.
If you want to calculate it, you can do it as given below:
P(A or B or C was born in a leap year) = 1/4 + 1/4 + 1/4 - 1/16 - 1/16 - 1/16 + 1/64 = 1/2 + 1/16 + 1/64 (same as the sets concept)
This is definitely more than 50%.
Answer (C)
#If one is selected P(A born in a leap year) = 1/4 or 25%
#If two are selected the probability that
at least one is born in a leap year P(A only, B only, or A & B) = P(A) + P(B) + P(A&B) = (1/4 * 3/4) + (3/4 * 1/4) + (1/4 * 1/4) = 7/16
From here I just made the assumption that 3 people would push it above 50% and selected C.
I am just curious of the method that
VeritasPrepKarishma used... Maybe there is a Thread or Blog post you could point me to that explains this in more detail.
Thanks in advance!
This method is a counterpart of SETS formulas we use.
10 people like A and 20 people like B. 5 like both A and B. So how many people like A or B?
n(A or B) = n(A) + n(B) - n(A and B)
We subtract n(A and B) because it is counted twice - once in n(A) and another time in n(B). But we want to count it only once so subtract it out once.
n(a or B) gives us the number of people who like at least one of A and B.
Similarly, we can use this method for probability
p(A or B) = p(A) + p(B) - p(A and B)
It is exactly the same concept. It gives us the probability that at least one of two people are born in a leap year.
When considering p(A), p(B) is to be ignored and when c considering p(B), p(A) is to be ignored. We take care of both when we subtract p(A and B).
Similarly, we can use the sets concept for 3 people using the three overlapping sets formula:
n(A or B or C) = n(A) + n(B) + n(C) - n(A and B) - n(B and C) - n(C and A) + n(A and B and C)
it becomes
p(A or B or C) = p(A) + p(B) + p(C) - p(A and B) - p(B and C) - p(C and A) + p(A and B and C)