Bunuel chetan2uIf you have a moment, I just wanted to clarify that I am reading the question correctly.
In statement 1, when we are told “the probability of getting an X on EITHER of the two times” —-/> is the meaning as follows?
Because they are independent events, any time she throws the die, she has a 1 in 5 chance of X showing up. In other words, any time she throws the die the Probability of an X showing up = (1/5)
I initially interpreted the meaning as follows:
P of getting an X on either of the 2 times =
(P of getting X on 1st throw AND getting any other number on 2nd throw)
+
(P of getting any other number on 1st throw AND getting X on 2nd throw)
+
(P of getting X on 1st throw AND X on 2nd throw)
I believe I wasn’t reading the statement close enough. The singular “die” is used. Therefore, I should be understanding the meaning as:
For any independent throw that she makes, she has a (1/5) chance of getting the X to show up.
Am I interpreting the statement correctly? Just looking to clarify and any help would be appreciated. Thank you.
Edit: and I missed the official explanation from Princeton review that someone posted.
There is only one X # on one face, so the Probability of X showing up must have a 1 in the Numerator.
If the probability of getting an x when she “throws the DIE” is = (1/5)
Then there must be 5 consecutive numbers on the die.
Macedon wrote:
Rachel is throwing a die with sides numbered consecutively from 1 to x. What is the probability that she gets at least one x?
(1) The probability of getting an x on either of the two times that Rachel throws the die is 1/5.
(2) If Rachel had thrown the die one more time, the probability of getting at least one x would have been 61/125.
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