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Re: The ratio, by weight, of the four ingredients A, B, C, and D of a cert [#permalink]
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Lets say our thing has the weight X(4+7+8+12) = 31*X. When we change mixture our weight changes to X(4 + 7 + 2 + 12*Y) =13*X+12*X*Y
We also know that 7*X = 0,2(13*X+12*X*Y). Need to find Y.
Reduce that last equation by X and lets just solve it for Y: Y = (7 - 0,2*13)/2,4 = 44/24 = 11/6
So the original ratio was 4/12 = 1/3
The new ratio is 1*6/(3*11) = 2/11
The resulting percentages are: (1/3-2/11)/(1/3) = 1 - 6/11 = 5/11 = 0,454 ~ 45%

Answer ends up being "D"
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Re: The ratio, by weight, of the four ingredients A, B, C, and D of a cert [#permalink]
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I guess answer is B .
original ratio A:B:C:D = 4:7:8:12
in ratio , A:C is quardapled , and A:B is constant
Hence ,
New ratio = 16:B:32:D
since ,A:B is constant , Find B from above two equations , which comes as 28
so new ratio =16:28:32:D

Now it is told that B constitutes , 20% of new mixture .
28=20/100 (new mixture)
so New mixtre quantity = 140

so
16:28:32:D =140
Hence D=64
hence ratio of A:D in new mixture= 16:64=25%
In old mixture = 4:12=33.33%

Change = (33.33-25)/33.33 = 8.33/33.33 which is approximately 25%
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Re: The ratio, by weight, of the four ingredients A, B, C, and D of a cert [#permalink]
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Bunuel wrote:
The ratio, by weight, of the four ingredients A, B, C, and D of a certain mixture is 4:7:8:12. The mixture will be changed so that the ratio of A to C is quadrupled and the ratio of A to D is decreased. The ratio of A to B will be held constant. If B will constitute 20% of the weight of the new mixture, by approximately what percent will the ratio of A to D be decreased?

A. 15%
B. 25%
C. 35%
D. 45%
E. 55%

Kudos for a correct solution.


Given :
The ratio of A to B will be held constant and B is not changed , so 'A' is also not changed.
If 'A' is not changed then the only way A:C will be quadrupled is by reducing C , from C to C/4 .
A:D is decreased , again 'A' is not changed , so , D is increased.
In new mixture B is 20% , so A+C+Dis 80% .

Asked :

\(\frac{Old_{A:D } - New_{A:D }}{Old_{A:D }}*100\)

Solution:

A:B:C:D=4:7:8:12
Old : 4x , 7x, 8x, 12x

\(Old_{A:D } = \frac{1}{3}\)

New : 4x, 7x, 2x, UNKNOWN,Say 'Y' (>12x)

we are told that 7x=20%( 4x+7x+2x+y)====>35x=13x+y======>22x=y

\(New_{A:D } = \frac{4x}{22x}\)

\(\frac{Old_{A:D } - New_{A:D }}{Old_{A:D }}*100\) = 45%

Answer C
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Re: The ratio, by weight, of the four ingredients A, B, C, and D of a cert [#permalink]
VeritasPrepKarishma wrote:
Bunuel wrote:
The ratio, by weight, of the four ingredients A, B, C, and D of a certain mixture is 4:7:8:12. The mixture will be changed so that the ratio of A to C is quadrupled and the ratio of A to D is decreased. The ratio of A to B will be held constant. If B will constitute 20% of the weight of the new mixture, by approximately what percent will the ratio of A to D be decreased?

A. 15%
B. 25%
C. 35%
D. 45%
E. 55%

Kudos for a correct solution.


Start with what you know so that use of variables is minimized.

A:B:C:D = 4:7:8:12
B is 20% of the weight of new mixture so 7 parts is 20% of the weight. This means total weight of the new mixture is 35 parts.
Ratio of A:B remains constant so 4:7.
Ratio of A:C (4:8) is quadrupled (4*4:8 = 2:1). Since A is 4 parts, C must be 2 parts.

4:7:2:D
Total must add up to 35 parts. So D must be 35 - (4 + 7 + 2) = 22 parts.

A:D ratio has changed from 4:12 (1/3) to 4:22 (2/11). This is a decrease of (1/3 - 2/11)/(1/3) * 100 = 45% approx



You solved the complete Q there itself, awesome. Thanks for updating your solution.

Regards,
Gaurav
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Re: The ratio, by weight, of the four ingredients A, B, C, and D of a cert [#permalink]
KarishmaB wrote:
Bunuel wrote:
The ratio, by weight, of the four ingredients A, B, C, and D of a certain mixture is 4:7:8:12. The mixture will be changed so that the ratio of A to C is quadrupled and the ratio of A to D is decreased. The ratio of A to B will be held constant. If B will constitute 20% of the weight of the new mixture, by approximately what percent will the ratio of A to D be decreased?

A. 15%
B. 25%
C. 35%
D. 45%
E. 55%

Kudos for a correct solution.


Start with what you know so that use of variables is minimized.

A:B:C:D = 4:7:8:12
B is 20% of the weight of new mixture so 7 parts is 20% of the weight. This means total weight of the new mixture is 35 parts.
Ratio of A:B remains constant so 4:7.
Ratio of A:C (4:8) is quadrupled (4*4:8 = 2:1). Since A is 4 parts, C must be 2 parts.

4:7:2:D
Total must add up to 35 parts. So D must be 35 - (4 + 7 + 2) = 22 parts.

A:D ratio has changed from 4:12 (1/3) to 4:22 (2/11). This is a decrease of (1/3 - 2/11)/(1/3) * 100 = 45% approx

Why can’t we multiply 8 with 4,since the ratio b/w them is quadrupuled
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Re: The ratio, by weight, of the four ingredients A, B, C, and D of a cert [#permalink]
Bunuel wrote:
The ratio, by weight, of the four ingredients A, B, C, and D of a certain mixture is 4:7:8:12. The mixture will be changed so that the ratio of A to C is quadrupled and the ratio of A to D is decreased. The ratio of A to B will be held constant. If B will constitute 20% of the weight of the new mixture, by approximately what percent will the ratio of A to D be decreased?

A. 15%
B. 25%
C. 35%
D. 45%
E. 55%

Kudos for a correct solution.

­





Given, A:B:C:D = 4:7:8:12
A:B is constant i.e. A:B=4:7
A:C is quadrupled i.e. A/C = (4/8)*4=2:1=4:2
Therefore, A:B:C:D=4:7:2:D. I am assuming value of D is D since A:D decreses.
B comprises 20% of mixture i.e. 7/(13+D) = 20/100 or, D=22.
Previously, A/D=4/12. Now, A/D=4/22.
So, (4/12 - 4/22) / (4/12) *100 = 45.45 ~ 45%. Option (D) is correct.
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Re: The ratio, by weight, of the four ingredients A, B, C, and D of a cert [#permalink]
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