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Re: If x is a nonzero number, which of the three numbers x, 1/x [#permalink]
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If x is a nonzero number, which of the three numbers x, 1/x and x^2 is greatest?

(1) -1 < x < 1 We know that x is a fraction, but we don't know if it is negative or positive. If x is -1/2, then we have -1/2, -2, and 1/4 (x^2 is greatest). If x is 1/2 we have 1/2, 2, and 1/4, making (1/x greatest)
(2) x is negative We can answer this knowing the sign of x (again, take -1/2 as the example)
B
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Re: If x is a nonzero number, which of the three numbers x, 1/x [#permalink]
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Hi sidney123,

Your approach to TEST VALUES is a good one, but you have to do the necessary work (on the pad, so you can "see" it) to make sure that you're selecting the correct answer.

Here, we're asked to consider X, 1/X and X^2.....We're asked which is GREATEST.

Fact 2 tells us that X is NEGATIVE....

Using your two examples, we'd end up with....

X = -2
1/X = -1/2
X^2 = (-2)^2 = 4
So X^2 is the greatest

X = -1/2
1/X = 1/(-1/2) = -2
X^2 = (-1/2)^2 = 1/4
So X^2 is the greatest

The two examples yield the SAME result. Based on what we're told in Fact 2, X will ALWAYS be NEGATIVE, 1/X will ALWAYS be NEGATIVE and X^2 will ALWAYS be POSITIVE, so the answer will ALWAYS be X^2. Thus, Fact 2 is SUFFICIENT.

As you continue to practice DS, whenever you think a Fact is insufficient, you should be able to quickly prove it. Doing that little bit of extra work can pick you up a LOT of points in the Quant section.

Final Answer:

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Re: If x is a nonzero number, which of the three numbers x, 1/x [#permalink]
Thankyou for all your input guys, really appreciate the time and effort taken to explain the simple problem. For some reason, I read the Q wrong(I don't know why?), I was looking at arranging x, 1/x and x^2 from smallest to greatest, in which case we need both statements. But the Q asks for which is greatest and stmt.2 is sufficient.
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Re: If x is a nonzero number, which of the three numbers x, 1/x [#permalink]
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goodyear2013 wrote:
If x is a nonzero number, which of the three numbers x, 1/x and x^2 is greatest?

(1) -1 < x < 1
(2) x is negative


Hi, can anyone explain St(2), please.


Given: x is a nonzero number

Target question: Which of the three numbers x, 1/x and x² is greatest?

Statement 1: -1 < x < 1
This statement doesn't FEEL sufficient, so I'll TEST some values.
There are several values of x that satisfy statement 1. Here are two:
Case a: x = 1/2. This means 1/x = 1/(1/2) = 2, and x² = (1/2)² = 1/4. In this case, the answer to the target question is 1/x is the greatest value
Case b: x = -1/2. This means 1/x = 1/(-1/2) = -2, and x² = (-1/2)² = 1/4. In this case, the answer to the target question is x² is the greatest value
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Aside: For more on this idea of testing values when a statement doesn't feel sufficient, read my article: https://www.gmatprepnow.com/articles/dat ... lug-values

Statement 2: x is negative
This means 1/x = 1/negative = negative, and x² = (negative,)² = positive.
Since x² is positive, and x and 1/x are negative, the answer to the target question is x² is definitely the greatest value
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer: B

Cheers,
Brent
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Re: If x is a nonzero number, which of the three numbers x, 1/x [#permalink]
goodyear2013 wrote:
If x is a nonzero number, which of the three numbers x, 1/x and x^2 is greatest?

(1) -1 < x < 1
(2) x is negative


Hi, can anyone explain St(2), please.


(1) Clearly insufficient.

(2) If \(x < 0\), then lets say \(x = -1\)

\(x = -1\)
\(\frac{1}{x} = -1\)
\(x^2 = 1\)

\(x^2\) is the greatest. SUFFICIENT.

Answer is B.
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Re: If x is a nonzero number, which of the three numbers x, 1/x [#permalink]
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Re: If x is a nonzero number, which of the three numbers x, 1/x [#permalink]
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