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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
If 320 people attended the wedding and 200 attendees drank wine, how many attendees drank neither beer nor wine?
(1) There were the same number of beer drinkers as nondrinkers.
(2) The same number of people drank only beer as drank both beer and wine.


As per Set theory, we can write -
Total no of Attendees= No of people drinking only Wine+ No of people drinking only BEER - No of people drinking both Wine & Beer + No of people drinking None
320= 200 + Beer only - Both + None
120 = Beer only - Both + None -----(Equation 1)

We need to find the value of NONE
Statement 1- Beer only = None
By using this info & equation 1 we can not find the value of None.
Thus Insufficient

Statement 1- Beer only = Both
By using this info & equation 1 we can find the value of None.
Thus Sufficient

So the answer for this question has to be B.

Hope this detailed explanation will help many.

Fame
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
fameatop wrote:
If 320 people attended the wedding and 200 attendees drank wine, how many attendees drank neither beer nor wine?
(1) There were the same number of beer drinkers as nondrinkers.
(2) The same number of people drank only beer as drank both beer and wine.


As per Set theory, we can write -
Total no of Attendees= No of people drinking only Wine+ No of people drinking only BEER - No of people drinking both Wine & Beer + No of people drinking None
320= 200 + Beer only - Both + None
120 = Beer only - Both + None -----(Equation 1)

We need to find the value of NONE
Statement 1- Beer only = None
By using this info & equation 1 we can not find the value of None.
Thus Insufficient

Statement 1- Beer only = Both
By using this info & equation 1 we can find the value of None.
Thus Sufficient

So the answer for this question has to be B.

Hope this detailed explanation will help many.

Fame


Your equation is wrong as indicated by red part.....Make sure of it
Correct one is:
Total = Beer dinker + wine drinker - both + Neither
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
I think, I am too tired. Pardon for the mistake
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
I am confused becasue of the wording of the first statement. What does non drinker mean? Is it the one who does not drink beer or it is referring to the people who drink neither of the drink.

Interpretation of this statement in different ways gives two different answer....

Someone shed some light....

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Atal Pandit
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
Bunuel wrote:
If 320 people attended the wedding and 200 attendees drank wine, how many attendees drank neither beer nor wine?

{Total} = {Wine} + {Beer} - {Both} + {Neither}
320 = 200 + {Beer} - {Both} + {Neither}
120 = {Beer} - {Both} + {Neither}
{Neither} = ?

(1) There were the same number of beer drinkers as nondrinkers:
{Beer} = {Neither}
120 = {Neither} - {Both} + {Neither}
120 = 2*{Neither} - {Both}.
Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine:
{Beer} - {Both} = {Both}
{Beer} = 2*{Both}
120 = 2*{Both} - {Both} + {Neither}

120 = {Both} + {Neither}.
Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Answer: C.

Hope it's clear.


Your solution is awesome..... Could you elaborate the red part?
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
Expert Reply
atalpanditgmat wrote:
Bunuel wrote:
If 320 people attended the wedding and 200 attendees drank wine, how many attendees drank neither beer nor wine?

{Total} = {Wine} + {Beer} - {Both} + {Neither}
320 = 200 + {Beer} - {Both} + {Neither}
120 = {Beer} - {Both} + {Neither}
{Neither} = ?

(1) There were the same number of beer drinkers as nondrinkers:
{Beer} = {Neither}
120 = {Neither} - {Both} + {Neither}
120 = 2*{Neither} - {Both}.
Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine:
{Beer} - {Both} = {Both}
{Beer} = 2*{Both}
120 = 2*{Both} - {Both} + {Neither}

120 = {Both} + {Neither}.
Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Answer: C.

Hope it's clear.


Your solution is awesome..... Could you elaborate the red part?


The second statement states that {Beer} - {Both} = {Both} thus {Beer} = 2*{Both}. Now, substitute {Beer} = 2*{Both} into 120 = {Beer} - {Both} + {Neither} to get 120 = 2*{Both} - {Both} + {Neither}.

Hope it's clear.
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
Bunuel wrote:
If 320 people attended the wedding and 200 attendees drank wine, how many attendees drank neither beer nor wine?

{Total} = {Wine} + {Beer} - {Both} + {Neither}
320 = 200 + {Beer} - {Both} + {Neither}
120 = {Beer} - {Both} + {Neither}
{Neither} = ?

(1) There were the same number of beer drinkers as nondrinkers:
{Beer} = {Neither}
120 = {Neither} - {Both} + {Neither}
120 = 2*{Neither} - {Both}.
Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine:
{Beer} - {Both} = {Both}
{Beer} = 2*{Both}
120 = 2*{Both} - {Both} + {Neither}
120 = {Both} + {Neither}.
Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Answer: C.

Hope it's clear.


could you solve it for me please so i can see how this works out
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
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madzstar wrote:
Bunuel wrote:
If 320 people attended the wedding and 200 attendees drank wine, how many attendees drank neither beer nor wine?

{Total} = {Wine} + {Beer} - {Both} + {Neither}
320 = 200 + {Beer} - {Both} + {Neither}
120 = {Beer} - {Both} + {Neither}
{Neither} = ?

(1) There were the same number of beer drinkers as nondrinkers:
{Beer} = {Neither}
120 = {Neither} - {Both} + {Neither}
120 = 2*{Neither} - {Both}.
Two unknowns. Not sufficient.

(2) The same number of people drank only beer as drank both beer and wine:
{Beer} - {Both} = {Both}
{Beer} = 2*{Both}
120 = 2*{Both} - {Both} + {Neither}
120 = {Both} + {Neither}.
Two unknowns. Not sufficient.

(1)+(2) We have that 120 = 2*{Neither} - {Both} and 120 = {Both} + {Neither}. We have two unknowns and two linear equation, thus we can solve. Sufficient.

Answer: C.

Hope it's clear.


could you solve it for me please so i can see how this works out


Sum the equations: 240 = 3*{Neither} --> {Neither} = 80.

Hope it helps.
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
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Hi Bunuel - for Statement (2), it sounds like Beer = Both. Can you explain why this is not true?
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
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cg0588 wrote:
Hi Bunuel - for Statement (2), it sounds like Beer = Both. Can you explain why this is not true?


Check here: if-320-people-attended-the-wedding-and-200-attendees-drank-153185.html#p1227863
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
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Presenting the matrix approach to the solution

Question statement

Question statement tells us that total number of attendees are 320 out of which 200 drank wine i.e. the remaining 120 either drank only beer or did not drink at all.



Statement- I

Statement-I tells us that number of attendees who drank beer and number of attendees who did not drink anything were same. Let's assume them as x and populate the rest of the matrix.



We see that we do not get any relation through which we can find the value of x. Hence st-I is insufficient to answer the question

Statement-II

St-II tells us that same number of people drank only beer as both beer and wine. Let's assume the number of people as y and populate the rest of the matrix.



We see that we do not get any relation through which we can find the value of y. Hence st-II is insufficient to answer the question.

Combining Statement- I & II

Considering the matrix of statement-I and using the information given in st-II we get the equation as 120 - x = 2x - 120 which gives us x = 80 i.e number of attendees who drank neither beer nor wine.

Thus combining both the statements is sufficient to answer the question.

Hope this helps :)

Regards
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If 320 people attended the wedding and 200 attendees drank [#permalink]
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reto wrote:
Hey Harley

Could you explain me why Beer is not equal to "both" as the statement 2 says. I really don't understand why ..... :( "(2) The same number of people drank only beer as drank both beer and wine"

Would be awesome :)

Thanks



Hello reto.
In "overlapping sets" tasks you should pay big attention on words 'exactly' and 'only'

Beer drinkers are all people who drink beer and also wine. Some of them drink beer only and some of them both beer and wine.
Statement 2 says that 'beer only' drinkers equal to people who drink wine and beer.

Let's write some facts about this task:

Total people = 320
Beer = 80
Wine 200
Beer and wine = 40
Neither = 80

Beer only = Beer - both = 80 - 40 = 40
Wine only = Wine - both = 200 - 40 = 160

So when statement says that beer equal to neither we can write it as: beer = 80 = neither = 80
and when statement says beer ONLY equal to both we can write it as: beer only = 40 = both = 40
and from this statement we can infer that beer(80) - both(40) = beer only = 40

Does that make sense?
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
Total 320 people are there
200 people drink wine
Let x no. of people drink both wine and beer

Case 1: There were the same number of beer drinkers as nondrinkers.
Let beer drinkers be a and hence non drinkers be a too

Therefore total (200-x)+(a-x)+a=320
=> 2a-2x=120
Not sufficient

Case 2:The same number of people drank only beer as drank both beer and wine.
Taking variables from above
Let the number of people drink both beer and wine and only beer be y

and the number of people who do not drink anything be s

200 - y + y + s = 320
s = 120

Hence B
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
cg0588 wrote:
Hi Bunuel - for Statement (2), it sounds like Beer = Both. Can you explain why this is not true?



I was hung up on this problem for a long time and asking myself this same question. This post is 5 years old but for those that may be in my shoes and revisiting:

The term "Beer = Both" is meaning "ALL beer" = both. think of "all beer" as one whole circle of a venn diagram. The correct way is to consider those who drank ONLY beer = drank both. So the whole circle of the venn diagram would be ALL that drank Beer = those that ONLY Beer + those that drank Both

so ONLY Beer = Both
ALL Beer = Both + Both, or (2)Both

Plug that in to your equation of
120=ALL Beer - Both + Neither
120=(2)Both - Both + Neither
120= Both + Neither

As you can see. we still can't solve for "both" or "neither".
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
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Re: If 320 people attended the wedding and 200 attendees drank [#permalink]
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