Harley1980 wrote:
When 120 is divided by positive single-digit integer \(m\) the remainder is positive. When 120 is divided by positive integer \(n\) the remainder is also positive. If \(m<>n\) what is the remainder when 120 is divided by \(|n-m|\)?
1) When 120 divided by integer \(n\) the remainder equal to \(\sqrt{n}\)
2) \(n\) is a single-digit integer
Source: self-made
Hi
Harley1980,
The solution given by you along with OA is not correct..
The solution is as follows..
1) When 120 divided by integer \(n\) the remainder equal to \(\sqrt{n}\)From this statement we know that N is 9 as found by you..
But is 9 the only value possible..
The second value is staring at us right in the Q..Any value of n >120 will leave a remainder 120..
so 120^2 will also leave a remainder 120..
Second value of n, therefore, is 120^2..
At least two possible values of n: 9 and 120^2..
Insuff
2) \(n\) is a single-digit integer When we divide \(120\) by single-digit positive integer only two numbers give remainder: \(9\) and \(7\) and we know that \(m \neq n\) so we can infer that there are two possible cases
1) \(m = 7\) and \(n =9\)
2) \(m=9\) and \(n = 7\)
\(|9-7| = 2\)
\(|7-9| = 2\)
\(120/2 = 60\) Remainder is \(0\)
Sufficient
Answer is B
I am changing the OA. Please revert if any query..
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