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Two cars start at the same time from opposite ends of a highway that

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Bunuel
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Two cars start at the same time from opposite ends of a highway that [#permalink] New post   02 Jun 2016, 04:35
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Two cars start at the same time from opposite ends of a highway that is 45 miles long. One car is riding at 14 mph and the second car is riding at 16 mph. How long after they begin will they meet?

(A) 1
(B) 1.2
(C) 1.25
(D) 1.35
(E) 1.5
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E
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink] New post   02 Jun 2016, 04:50
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Bunuel wrote:
Two cars start at the same time from opposite ends of a highway that is 45 miles long. One car is riding at 14 mph and the second car is riding at 16 mph. How long after they begin will they meet?

(A) 1
(B) 1.2
(C) 1.25
(D) 1.35
(E) 1.5



This is a representative problem of relative speed.

As cars are moving in opposite directions their speeds will be added. So their relative speeds: 16+14 = 30mph

Total distance to be covered = 45 miles.

Time taken would be: \(\frac{45 miles}{30mph}\) = 1.5 hours

E is the answer.
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink] New post   02 Jun 2016, 06:20
Bunuel wrote:
Two cars start at the same time from opposite ends of a highway that is 45 miles long. One car is riding at 14 mph and the second car is riding at 16 mph. How long after they begin will they meet?

(A) 1
(B) 1.2
(C) 1.25
(D) 1.35
(E) 1.5


Time they will meet = total distance/ relative speed= 45/14+16= 45/30= 1.5

Answer is E
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink] New post   05 Jun 2016, 13:35
Bunuel wrote:
Two cars start at the same time from opposite ends of a highway that is 45 miles long. One car is riding at 14 mph and the second car is riding at 16 mph. How long after they begin will they meet?

(A) 1
(B) 1.2
(C) 1.25
(D) 1.35
(E) 1.5



Let me assume that they meet after x hour

So for the First car ,traveled distance until they meet=14x mile

and for the Second car,traveled distance until they meet=16x mile

So,Total traveled distance=14x+16x=45 ,so x=\(\frac{3}{2}\)=1.5 hour

Correct answer E
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink] New post   05 Jun 2016, 13:46
Speed R=14+16=30
Total Distance=45
so, Time when they meet =45/30=1.5h
Correct answer is E.
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink] New post   06 Jun 2016, 03:49
relative speed = (16+14) = 30 mph (since they are travelling towards each other)
time = distance/speed = 45/30=3/2=1.5
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink] New post   15 Jun 2016, 13:55
We have to calculate the time they meet after beginnning their journey
Distance = 45 miles
Relative speed for 2 vehicles travelling in opposite directions is the sum of their speeds

Time = \(\frac{distance}{speed}\) =\(\frac{45}{(14+16)}\) = 1.5hrs

Correct Answer - E
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink] New post   26 Feb 2018, 10:41
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Bunuel wrote:
Two cars start at the same time from opposite ends of a highway that is 45 miles long. One car is riding at 14 mph and the second car is riding at 16 mph. How long after they begin will they meet?

(A) 1
(B) 1.2
(C) 1.25
(D) 1.35
(E) 1.5


We’ll use the distance formula d = r x t. We know that the sum of the distances that the two cars travel will total 45 miles. Letting t = the time it takes for the two cars to meet, we can create the following equation:

14t + 16t = 45

30t = 45

t = 45/30 = 3/2 = 1.5

Answer: E
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink] New post   07 Apr 2023, 10:46
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Re: Two cars start at the same time from opposite ends of a highway that [#permalink]
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