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Set A of 8 positive integers may have the same element and have 38. An

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MathRevolution
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Set A of 8 positive integers may have the same element and have 38. An [#permalink] New post   05 Jun 2016, 19:34
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55% (02:35) correct 45% (02:28) wrong based on 140 sessions
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Set A of 8 positive integers may have the same element and have 38. And set B of 8 positive integers must have different elements and have 38. When m and n are the greatest possible differences between 38 and other elements’ sums in set A and set B, respectively, m-n=?
A. 20
B. 21
C. 23
D. 25
E. 26

*An answer will be posted in 2 days.
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B
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MathRevolution
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Re: Set A of 8 positive integers may have the same element and have 38. An [#permalink] New post   07 Jun 2016, 18:44
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This is maximum-minimum. Hence, 38-(1+1+1+1+1+1+1)=31 and 38-(1+2+3+4+5+6+7)=10. So, 31-10=21. The correct answer is B.
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Daanu
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Re: Set A of 8 positive integers may have the same element and have 38. An [#permalink] New post   09 Jun 2016, 16:16
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Since, the ques says 'greatest possible difference'
Therefore,
38 - 7*a = m
only by placing a =1 the difference will be maximum.
Hence, 38 - 7*1 = 31
m = 31

Similarly
In second case all numbers should be different but difference has to be maximum..

Therefore, here also only 1 such case is possible..
Where set B = {1,2,3,4,5,6,7,38}

In this case only the difference would be max

Therefore
n = 38 - 28 = 10

So, m - n = 31-10 = 21 answer



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Re: Set A of 8 positive integers may have the same element and have 38. An [#permalink] New post   24 Nov 2016, 02:11
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Hi.
This Question clearly has language Issues.
When you say the difference between 38 and the other elements sum
There are two possible differences =>
Case 1=> Sum-Difference
Case2=> Difference -Sum

Apart from this the second statement in the Question is extremely messy.



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Stone Cold
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Re: Set A of 8 positive integers may have the same element and have 38. An [#permalink] New post   24 Nov 2016, 03:14
stonecold wrote:
Hi.
This Question clearly has language Issues.
When you say the difference between 38 and the other elements sum
There are two possible differences =>
Case 1=> Sum-Difference
Case2=> Difference -Sum

Apart from this the second statement in the Question is extremely messy.



Regards
Stone Cold

Yes, I am also extremely confused by the wording of the question.
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Re: Set A of 8 positive integers may have the same element and have 38. An [#permalink] New post   24 Nov 2016, 03:58
Deciphering this question was a monumental task. I have no idea what is actually being tested in a question like this.
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Re: Set A of 8 positive integers may have the same element and have 38. An [#permalink] New post   06 Nov 2017, 07:37
MathRevolution wrote:
Set A of 8 positive integers may have the same element and have 38. And set B of 8 positive integers must have different elements and have 38. When m and n are the greatest possible differences between 38 and other elements’ sums in set A and set B, respectively, m-n=?
A. 20
B. 21
C. 23
D. 25
E. 26

*An answer will be posted in 2 days.

THE WORDING OF THIS QUESTION IS SLIGHTLY CONFUSING, GREATEST POSSIBLE DIFFERENCE BETWEEN 38 AND OTHER ELEMENTS SOME. WHAT IF I REVERSE THE SIGN I MEAN TO SAY IF THE SUM IS MORE THAN 38 DIFFERENCE WILL BE STILL GREATEST WITH A CHANGE IN SIGN.
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Re: Set A of 8 positive integers may have the same element and have 38. An [#permalink] New post   26 Oct 2022, 18:30
Hello from the GMAT Club BumpBot!

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Re: Set A of 8 positive integers may have the same element and have 38. An [#permalink]
26 Oct 2022, 18:30
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