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Lottery balls numbered consecutively from one through one hundred are

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Bunuel
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Lottery balls numbered consecutively from one through one hundred are [#permalink] New post   16 Aug 2016, 06:04
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Lottery balls numbered consecutively from one through one hundred are placed in a spinner. If one ball is drawn at random, what is the probability that it will have the number 1 on it exactly once?

A. 9/100
B. 1/10
C. 11/100
D. 19/100
E. 1/5
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D
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Senthil1981
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Re: Lottery balls numbered consecutively from one through one hundred are [#permalink] New post   16 Aug 2016, 08:01
Bunuel wrote:
Lottery balls numbered consecutively from one through one hundred are placed in a spinner. If one ball is drawn at random, what is the probability that it will have the number 1 on it exactly once?

A. 9/100
B. 1/10
C. 11/100
D. 19/100
E. 1/5


Probability = No of balls with exactly one 1 / total number of balls
= {1,10,12 to 19, 21,31,41,51,61,71,81,91,100}/100
= 19/100

Answer is D
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Lottery balls numbered consecutively from one through one hundred are [#permalink] New post   07 Oct 2016, 03:04
Bunuel wrote:
Lottery balls numbered consecutively from one through one hundred are placed in a spinner. If one ball is drawn at random, what is the probability that it will have the number 1 on it exactly once?

A. 9/100
B. 1/10
C. 11/100
D. 19/100
E. 1/5


Total possibilities = 100

Break the 1 - 100 into segments

1-9: only one possible outcome = 1
10-19: 1 _, now, in the '_' (units digit) you can have numbers 0 - 9, hence 1*10 = 10. But you need to remove '11' as the questions states '1 exactly once'. 10 - 1 = 9.
20 -29: 2 _, in the '_' only one possible outcome = 1, (remember, in the above case, we have '1' in the tenths place, so we needed to count all possible numbers in the units place)
30 - 39: 3 _, only one possible outcome in units place = 1,
This will repeat for 40-49 to 90-99.
100 will have 1 exactly once.

Ans: \(\frac{(1+9+8+1)}{100} = \frac{19}{100}\)
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Re: Lottery balls numbered consecutively from one through one hundred are [#permalink] New post   23 May 2018, 08:37
Probability = No of Favorable outcomes / Total Outcomes

Total Outcomes = 100

No of Favorable Outcomes = 17 ( 1 + 8 + 8 + 1 + 1 i.e Number 1 + Numbers 12,13..19 + Numbers 21,31..91 + Number 10 + Number 100 )

Hence Ans = D
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Re: Lottery balls numbered consecutively from one through one hundred are [#permalink] New post   24 May 2018, 17:33
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Bunuel wrote:
Lottery balls numbered consecutively from one through one hundred are placed in a spinner. If one ball is drawn at random, what is the probability that it will have the number 1 on it exactly once?

A. 9/100
B. 1/10
C. 11/100
D. 19/100
E. 1/5


Excluding the numbers 10 to 19, there are 10 numbers with the number 1 exactly once, from 1 to 100, inclusive. They are 1, 21, 31, 41, 51, 61, 71, 81, 91, and 100. Excluding 11, there are also 9 numbers with the number 1 exactly once, from 10 to 19, inclusive. They are 10, 12, 13, 14, 15, 16, 17, 18, and 19. So the probability is 19/100.

Answer: D
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Re: Lottery balls numbered consecutively from one through one hundred are [#permalink] New post   22 May 2022, 07:24
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Re: Lottery balls numbered consecutively from one through one hundred are [#permalink]
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