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Five consecutive integers have a sum N. If all the integers are increa

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Bunuel
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Five consecutive integers have a sum N. If all the integers are increa [#permalink] New post   30 Dec 2016, 05:02
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Five consecutive integers have a sum N. If all the integers are increased by the same amount so that the middle integer is doubled, what is the sum of the resulting numbers?

A. 2N
B. 2N + 1
C. 2N + 2
D. 2N + 3
E. 2N + 4
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Re: Five consecutive integers have a sum N. If all the integers are increa [#permalink] New post   30 Dec 2016, 06:49
(a-2)+(a-1)+a+(a+1)+(a+2)=N
5a=N
To double the middle term, we need to add 'a' to all the 5 terms, which means adding 5a(=N).
Resulting sum is 2N.
A.

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Re: Five consecutive integers have a sum N. If all the integers are increa [#permalink] New post   30 Dec 2016, 07:36
Resulting answer should be A

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Re: Five consecutive integers have a sum N. If all the integers are increa [#permalink] New post   30 Dec 2016, 08:18
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Bunuel wrote:
Five consecutive integers have a sum N. If all the integers are increased by the same amount so that the middle integer is doubled, what is the sum of the resulting numbers?

A. 2N
B. 2N + 1
C. 2N + 2
D. 2N + 3
E. 2N + 4


Let the 5 numbers be 1 , 2 , 3 , 4 & 5

Sum = 15 (N)

Middle no doubled is 6

Each number is increased by 3, so the numbers now becomes - 4 , 5 , 6 , 7 , 8

Sum of the numbers now is 30 (2N)

So, Answer will be (A) 2N
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Re: Five consecutive integers have a sum N. If all the integers are increa [#permalink]
30 Dec 2016, 08:18
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