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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
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buckkitty wrote:
At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?

A) m+1/2(m-k)
B) m+1/2((m-k)/k)m
C) (m*sqrt(m))/sqrt(k)
D)m^2/2k;
E) km^2

please show any work and explanations please. OA to follow.


m = k*(1+c)^2
m/k = (1+c)^2
(m/k)^(1/2) = 1+c
c= (m/k)^(1/2) - 1

the value of the watch in jan 1 1995 is:

m(1+c)
so m(1+(m/k)^(1/2) - 1)
= m(m/k)^(1/2))

that is C
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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
@Conocieur: Shouldn't the equation read

m = k*(1+c/100)^2 ? Since it says in the question, 'c percent more'..
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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
Bunuel wrote:
Thiagaraj wrote:
@Conocieur: Shouldn't the equation read

m = k*(1+c/100)^2 ? Since it says in the question, 'c percent more'..


Yes, it should.

At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?
A. m+1/2(m-k)
B. m+1/2((m-k)/k)m
C. (m*sqrt(m))/sqrt(k)
D. m^2/2k;
E. km^2

Price in 1992 - \(k\);
Price in 1993 - \(k*(1+\frac{c}{100})\);
Price in 1994 - \(k*(1+\frac{c}{100})^2=m\) --> \((1+\frac{c}{100})=\sqrt{\frac{m}{k}}\);
Price in 1995 - \(m*(1+\frac{c}{100})=m*\sqrt{\frac{m}{k}\).

Answer: C.


Shouldn't this year be raised by the third power? since its the third year.
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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
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fozzzy wrote:
Bunuel wrote:
Thiagaraj wrote:
@Conocieur: Shouldn't the equation read

m = k*(1+c/100)^2 ? Since it says in the question, 'c percent more'..


Yes, it should.

At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?
A. m+1/2(m-k)
B. m+1/2((m-k)/k)m
C. (m*sqrt(m))/sqrt(k)
D. m^2/2k;
E. km^2

Price in 1992 - \(k\);
Price in 1993 - \(k*(1+\frac{c}{100})\);
Price in 1994 - \(k*(1+\frac{c}{100})^2=m\) --> \((1+\frac{c}{100})=\sqrt{\frac{m}{k}}\);
Price in 1995 - \(m*(1+\frac{c}{100})=m*\sqrt{\frac{m}{k}\).

Answer: C.


Shouldn't this year be raised by the third power? since its the third year.


It is actually.

Price in 1994 is \(k*(1+\frac{c}{100})^2\) which is \(m\), so the price in 1995 is \(k*(1+\frac{c}{100})^2*(1+\frac{c}{100})\) or \(m*(1+\frac{c}{100})\).

Hope it's clear.
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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
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4112019 wrote:
At the end of each year, the value of a certain antique watch is c percent more than its
value one year earlier, where c has the same value each year. If the value of the watch
was k dollars on January1, 1992, and m dollars on January 1, 1994, then in terms of m
and k, what was the value of the watch, in dollars, on January 1, 1995 ?

A. m +1/2(m–k)
B. m +1/2(m - k)m
Cm square root m /square root k
D.\(m^2\)/2k
E. k\(m2\)


Value on Jan 1, 1992 = k
Value on Jan 1, 1993 = k(1+c/100)
Value on Jan 1, 1994 = \(k(1 + c/100)^2 = m\)
So, \((1 + c/100) = \sqrt{\frac{m}{k}}\)
Value on Jan 1 1995 = \(k(1+c/100)^3 = k(1 + c/100)^2 * (1 + c/100)\)
= \(m*\sqrt{\frac{m}{k}}\)

Yes, I generally prefer plugging in numbers but the calculations here are a little painful (with squares and roots) so using algebra is not a bad idea.
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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
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buckkitty wrote:
At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?

A. m+1/2(m-k)
B. m+1/2((m-k)/k)m
C. (m*sqrt(m))/sqrt(k)
D. m^2/2k;
E. km^2


We can make the following expressions:

Value of the watch in 1992 = k

Value of the watch in 1993 = k*(1 + c/100)

Value of the watch in 1994 = k*(1 + c/100)^2 = m

Value of the watch in 1995 = k*(1 + c/100)^3 = m(1 + c/100)

Since k*(1 + c/100)^2 = m (the value of the value in 1994), we have:

(1 + c/100)^2 = m/k

1 + c/100 = √(m/k)

Thus, the value of the watch in 1995 is:

m(1 + c/100) = m*√(m/k) = m*√m/√k

Answer: C
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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
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buckkitty wrote:
At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?

A. m+1/2(m-k)
B. m+1/2((m-k)/k)m
C. (m*sqrt(m))/sqrt(k)
D. m^2/2k;
E. km^2


For an algebraic approach, we need to recognize that the value of the watch increases by the same factor each year. So, for the ease of calculations, let's say that the value increases by a factor of F.

Aside: Notice that the answer choices do not include the variable c. This tells me that I don't need to keep that variable in my solution.

In 1992, the watch is valued at k dollars.
In 1993, the watch is valued at kF dollars (applying our constant increase of F)
In 1994, the watch is valued at kF² dollars
In 1995, the watch is valued at kF³ dollars
GREAT, we now know the value in 1995. However, when we check the answer choices, none match the expression kF³. So, we have some more work to do.

The question tells us that, in 1994, the watch is valued at m dollars.
So, we now know that kF² = m.
Let's solve this equation for F (you'll see why in a moment)
We get: F² = m/k
F = √(m/k)
We can rewrite this as: F = (√m)/(√k)

We know that the 1995 value = kF³ dollars.
Rewrite, to get the 1995 value = (kF²)(F)
If we replace kF² with m and replace F with (√m)/(√k), we get:
1995 value = (m)((√m)/(√k))
= (m√m)/(√k)
= C

Cheers,
Brent
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At the end of each year, the value of a certain antique watch is "c" [#permalink]
Bunuel wrote:
Thiagaraj wrote:
@Conocieur: Shouldn't the equation read

m = k*(1+c/100)^2 ? Since it says in the question, 'c percent more'..


Yes, it should.

At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?
A. \(m+\frac{1}{2}(m-k)\)

B. \(m+\frac{1}{2}*\frac{m-k}{k}*m\)

C. \(\frac{m√m}{√k}\)

D. \(\frac{m^2}{2k}\)

E. \(km^2\)


Price in 1992 - \(k\);

Price in 1993 - \(k*(1+\frac{c}{100})\);

Price in 1994 - \(k*(1+\frac{c}{100})^2=m\). From this we can get that \((1+\frac{c}{100})=\sqrt{\frac{m}{k}}\);

Price in 1995 - \(m*(1+\frac{c}{100})=m*\sqrt{\frac{m}{k}}\).

Answer: C.


I followed you up until half of the work for 1994.

Why are we isolating for the percentage (100 + c / 100) on on side?

And for 1995, why are we multiplying by m?
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CEdward wrote:
Bunuel wrote:
Thiagaraj wrote:
@Conocieur: Shouldn't the equation read

m = k*(1+c/100)^2 ? Since it says in the question, 'c percent more'..


Yes, it should.

At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?
A. \(m+\frac{1}{2}(m-k)\)

B. \(m+\frac{1}{2}*\frac{m-k}{k}*m\)

C. \(\frac{m√m}{√k}\)

D. \(\frac{m^2}{2k}\)

E. \(km^2\)


Price in 1992 - \(k\);

Price in 1993 - \(k*(1+\frac{c}{100})\);

Price in 1994 - \(k*(1+\frac{c}{100})^2=m\). From this we can get that \((1+\frac{c}{100})=\sqrt{\frac{m}{k}}\);

Price in 1995 - \(m*(1+\frac{c}{100})=m*\sqrt{\frac{m}{k}}\).

Answer: C.


I followed you up until half of the work for 1994.

Why are we isolating for the percentage (100 + c / 100) on on side?

And for 1995, why are we multiplying by m?


We are told that the value of the watch was "m" dollars on January 1, 1994 and since the value of the watch is "c" percent more than its value one year earlier, then in 1995 the value becomes \(m*(1+\frac{c}{100})\).

The question asks to express the value of the watch in 1995 (\(m*(1+\frac{c}{100})\)), in terms of "m" and "k". So, we need to express \(1+\frac{c}{100}\) in terms of "m" and "k". That's why we are expressing it as \((1+\frac{c}{100})=\sqrt{\frac{m}{k}}\) for 1994.

Hope it's clear.
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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
Given: At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year.
Asked: If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?

Let us assume that value of the watch becomes x times in 1 year; where x = (1+c/100)
January 1, 1992
Value of the watch = k $

January 1, 1994
2 year later
Value of the watch = m $
m = kx^2
\(x = \sqrt{\frac{m}{k}}\)

January 1, 1995
1 year later
Value of the watch = mx = m\sqrt{\frac{m}{k}}

IMO C
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Re: At the end of each year, the value of a certain antique watch is "c" [#permalink]
BrentGMATPrepNow wrote:
buckkitty wrote:
At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?

A. m+1/2(m-k)
B. m+1/2((m-k)/k)m
C. (m*sqrt(m))/sqrt(k)
D. m^2/2k;
E. km^2


For an algebraic approach, we need to recognize that the value of the watch increases by the same factor each year. So, for the ease of calculations, let's say that the value increases by a factor of F.

Aside: Notice that the answer choices do not include the variable c. This tells me that I don't need to keep that variable in my solution.

In 1992, the watch is valued at k dollars.
In 1993, the watch is valued at kF dollars (applying our constant increase of F)
In 1994, the watch is valued at kF² dollars
In 1995, the watch is valued at kF³ dollars
GREAT, we now know the value in 1995. However, when we check the answer choices, none match the expression kF³. So, we have some more work to do.

The question tells us that, in 1994, the watch is valued at m dollars.
So, we now know that kF² = m.
Let's solve this equation for F (you'll see why in a moment)
We get: F² = m/k
F = √(m/k)
We can rewrite this as: F = (√m)/(√k)

We know that the 1995 value = kF³ dollars.
Rewrite, to get the 1995 value = (kF²)(F)
If we replace kF² with m and replace F with (√m)/(√k), we get:
1995 value = (m)((√m)/(√k))
= (m√m)/(√k)
= C

Cheers,
Brent


BrentGMATPrepNow hi Brent, i used number plugging

K = 1
c=100%

so 1992 = 1
93 = 2
94= 4
95 = 8

so m= 4


but both C and D are correct answers in this case, arent they ? :?
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dave13 wrote:
BrentGMATPrepNow wrote:
buckkitty wrote:
At the end of each year, the value of a certain antique watch is "c" percent more than its value one year earlier, where "c" has the same value each year. If the value of the watch was "k" dollars on January 1, 1992, and "m" dollars on January 1, 1994, then in terms of "m" and "k", what was the value of the watch, in dollars, on January 1, 1995?

A. m+1/2(m-k)
B. m+1/2((m-k)/k)m
C. (m*sqrt(m))/sqrt(k)
D. m^2/2k;
E. km^2


For an algebraic approach, we need to recognize that the value of the watch increases by the same factor each year. So, for the ease of calculations, let's say that the value increases by a factor of F.

Aside: Notice that the answer choices do not include the variable c. This tells me that I don't need to keep that variable in my solution.

In 1992, the watch is valued at k dollars.
In 1993, the watch is valued at kF dollars (applying our constant increase of F)
In 1994, the watch is valued at kF² dollars
In 1995, the watch is valued at kF³ dollars
GREAT, we now know the value in 1995. However, when we check the answer choices, none match the expression kF³. So, we have some more work to do.

The question tells us that, in 1994, the watch is valued at m dollars.
So, we now know that kF² = m.
Let's solve this equation for F (you'll see why in a moment)
We get: F² = m/k
F = √(m/k)
We can rewrite this as: F = (√m)/(√k)

We know that the 1995 value = kF³ dollars.
Rewrite, to get the 1995 value = (kF²)(F)
If we replace kF² with m and replace F with (√m)/(√k), we get:
1995 value = (m)((√m)/(√k))
= (m√m)/(√k)
= C

Cheers,
Brent


BrentGMATPrepNow hi Brent, i used number plugging

K = 1
c=100%

so 1992 = 1
93 = 2
94= 4
95 = 8

so m= 4

but both C and D are correct answers in this case, arent they ? :?


At this point, you can conclude that the correct answer is either C or D.
From here, you'll have to test another set of values to eliminate one of the two remaining out two choices.
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