Bunuel wrote:
I came down to 7. I mean that I can do the task in 7 races.
First 5 races: all horses by five. We'll have the five winners.
Race 6: the winners of previous five races. We'll have the 3 winners.
Now it's obvious that #1 here is the fastest one (gold medal).
For the silver and bronze we'll have 5 pretenders:
1. #2 from the last sixth race,
2. #3 from the last sixth race,
3. the second one from the race with the Gold medal winner from the first five races,
4. the third one from the race with the Gold medal winner from the first five races,
5. the second one from the race with the one which took the silver in the sixth race
Race 7: these five horse: first and second in this one will have the silver and bronze among all 25.
Answer B (7).
Good Q. +1
Hi Bunuel,
I have a doubt regarding the solution. The question is asking for
Fastest 3 horses & not the Top 3 Winners.
Let me put it this way.
Suppose 2 separate races were conducted & timing (in minutes) of these 10 horses are as follows:
Race 1 - 5, 6, 7, 8 , 9, 10 minutes
Race 1 - 8 , 9, 10, 11, 12 minutes
Now you are picking 5 from race-1 & 8 from race 2 because these 2 horses are winners. But these 2 horses are not the fastest horses. The 2 fastest horses from this scenario would be 5 & 6 min.
As per me had the question asked
Top 3 horses then your logic would be completely right but instead the question is asking for the fastest 5.
Kindly throw some light this logic.
Your inputs are always valuable.