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Re: On a business trip, 30 percent of 60 sales representatives will be [#permalink]
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thanks....thats how i thought about it but was wondering if there is a different method/way of thinking through it....lets see if more people post...
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Re: On a business trip, 30 percent of 60 sales representatives will be [#permalink]
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zisis wrote:
On a business trip, 30 percent of 60 sales representatives will be given accommodations at Hotel XYZ and the remaining 70 percent will be given accommodations at Hotel ABC. However, 55 percent of the sales representatives prefer to stay at Hotel XYZ and 45 percent prefer to stay at Hotel ABC. What is the highest possible number of sales representatives NOT given accommodations at the hotel they prefer?

A 11
B 18
C 36
D 45
E 51


very weird question....cannt even classify it...


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Re: On a business trip, 30 percent of 60 sales representatives will be [#permalink]
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.................. ABC ...................... XYZ .................. Total

Actual ......... 42 ......................... 18 ....................... 60

Prefer .......... 27 ......................... 33 ..................... 60

18 + 33 = 51

Answer = E
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Re: On a business trip, 30 percent of 60 sales representatives will be [#permalink]
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Hi All,

While this prompt is "thick" with data, the math involved isn't too bad (you just have to stay organized and label your work).

The first sentence gives us data about the number of reps (out of 60) who will stay at each hotel:

Hotel XYZ = (.30)(60) = 18 reps
Hotel ABC = the rest = 42 reps

Next, we're told about the PREFERENCES of the reps

Hotel XYZ = (.55)(60) = 33 reps PREFER to stay at this hotel
Hotel ABC = (.45)(60) = 27 reps PREFER to stay at this hotel

From this, we can clearly see that some of the reps (at least 15) who want to stay at XYZ will NOT get what they want because there are not enough spots.

We're asked for the MAXIMUM number of reps who would NOT be assigned to the hotel that they prefer....

Here, we're limited by the number of reps who COULD stay at each hotel.

There are only 18 'reservations' at Hotel XYZ, so we can shift 18 reps from ABC to XYZ (making 18 reps who DON'T get what they want).
Next, we can put the remaining 42 people in ABC (making 33 reps who DON'T get what they want and 9 who DO).

Total reps who DON'T get what they want = 18+33 = 51

Final Answer:

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Re: On a business trip, 30 percent of 60 sales representatives will be [#permalink]
30% of 60 sales representatives = 18 representatives are staying at XYZ.
Remaining 70% i.e. 42 representatives are staying at ABC.
55% i.e. 33 representatives prefer to stay at XYZ.
45% i.e. 27 representatives prefer to stay at ABC.
Maximum representative not staying at preferred place is when all 33 representatives who prefer to stay at XYZ are staying at ABC and only 9 representatives who prefer to stay at ABC are staying at ABC.
So, highest number = 33 + 18 = 51 representatives are not staying at their preferred place
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Re: On a business trip, 30 percent of 60 sales representatives will be [#permalink]
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On a business trip, 30 percent of 60 sales representatives will be given accommodations at Hotel XYZ and the remaining 70 percent will be given accommodations at Hotel ABC. However, 55 percent of the sales representatives prefer to stay at Hotel XYZ and 45 percent prefer to stay at Hotel ABC. What is the highest possible number of sales representatives NOT given accommodations at the hotel they prefer?

A 11
B 18
C 36
D 45
E 51

Actual

30% of 60 = 18 (IN XYZ)
70% of 60 = 42 (IN ABC)

Preference-

55% - 33 in XYZ
45% - 27 in ABC

18 at Hotel ABC XYZ be shifted to ABC

33 out of 42 at hotel ABC can be shifted to XYZ

18+33= 51.

MAXIMUM IS 51
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Re: On a business trip, 30 percent of 60 sales representatives will be [#permalink]
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