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# Power prep question

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13 Aug 2007, 11:27
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Can anybody explain sol to this problem
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13 Aug 2007, 11:29
Q. Given: x>y^2>z^4
I: x>y>z
II: z>y>x
III: x>z>y
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13 Aug 2007, 11:52
Quote:
Q. if x>y^2>z^4, which of the following could be correct?
I: x>y>z
II: z>y>x
III: x>z>y

I is sufficient: x = 2, y = 1/2, z = 1/4
II is sufficient: x = 3/20, y = 1/5, z = 1/4
III is sufficient: x=2, y = 1/4, z = 1/3

All of the above.
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