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Power prep question [#permalink] New post 13 Aug 2007, 10:27
Can anybody explain sol to this problem
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Intern
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 [#permalink] New post 13 Aug 2007, 10:29
Q. Given: x>y^2>z^4
I: x>y>z
II: z>y>x
III: x>z>y
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 [#permalink] New post 13 Aug 2007, 10:52
Quote:
Q. if x>y^2>z^4, which of the following could be correct?
I: x>y>z
II: z>y>x
III: x>z>y



I is sufficient: x = 2, y = 1/2, z = 1/4
II is sufficient: x = 3/20, y = 1/5, z = 1/4
III is sufficient: x=2, y = 1/4, z = 1/3

All of the above.
  [#permalink] 13 Aug 2007, 10:52
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