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# Powerprep - Mean, Median, Range

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Manager
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Powerprep - Mean, Median, Range [#permalink]  30 Apr 2007, 08:24
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Re: Powerprep - Mean, Median, Range [#permalink]  30 Apr 2007, 10:30
suniluic wrote:

1. suppose
S = 1,2,3,4,5,6,7,8 & 9
T = 1,2,3,4,6,7,8 & 9

mean of S = mean T = 5

2. suppose
S = 1,2,3,4,5,6,7,8 & 9
T = 1,2,3,4,6,7,8 & 9

median of S = median of T = 5

3. suppose
S = 1,2,3,4,5,6,7,8 & 9
T = 1,2,3,4,6,7,8 & 9

range of S = range of T = 8

4. suppose
S = 1,2,3,4,5,6,7,8 & 9
T = 1,2,3,4,5, 6,7, & 8

mean of S is 5 > mean of T is 4.5

5. suppose
S = 1,2,3,4,5,6,7,8 & 9
T = 1,2,3,4,5,6,7, & 8

the highest range of S is 8, which is also the highest range of T as well. therefore range of S cannot be smaller than the range of T.

So E is incorrect.
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T belongs to S then the range of S can not be smaller than the range of T.

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Re: Powerprep - Mean, Median, Range [#permalink]  01 May 2007, 08:22
If the second set is contained in the 1st, itÂ´ll always be possible that both have the same mean, median, range. What will never happen is that the second set, a subset of the 1st one, has a greater range. Thus, E.

Also, if you are going to scan or post images directly from the tests, please reduce/resize them, itÂ´s a bit unconfortable to read from those extra-bulky images. Thanx
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Re: Powerprep - Mean, Median, Range [#permalink]  01 May 2007, 09:28
I just used a smaller sample so it's easier to handle.

S contains 1, 2, 3, 4, 5
T could be any of the four numbers in S.

Mean of S = 3
Range of S = 5-1 = 4
Median of S = 3

We can pick any of the 4 numbers (without repeats) in Set T to test the statements.

A. If T contains 1, 2, 4, 5. Mean of T = 3
B. If T contains 1, 2, 4, 5. Median of T is 3
C. If T contains 1, 2, 4, 5. Range of T is 5-1=4
D. If T contains 1, 2, 3, 4. Mean of T = 2.5, which is less than Mean of S.
E. Range of S is 4. Here, no matter which 4 numbers you pick for T you can get a range that is greater than 4.

Re: Powerprep - Mean, Median, Range   [#permalink] 01 May 2007, 09:28
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