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# PR '05 A teacher uses ten flash cards, numbered 1 through

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PR '05 A teacher uses ten flash cards, numbered 1 through [#permalink]  11 Sep 2005, 17:10
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PR '05

A teacher uses ten flash cards, numbered 1 through 10, to teach students to order numbers correctly. She has students choose 4 cards randomly, then arrange the cards in ascending order. One day she removes cards '2' and '4' from the deck. On that day, how many differenct arrangements of four randomly selected cards are possible?
A) 70
B) 210
C) 336
D) 840
E) 1680
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[#permalink]  01 Oct 2005, 20:26
This is a combinations problem so you need to use the correct formula:

10-2 cards =8 total cards. all possible permuations of 4 chosen from 8 cards are 8!/4!(8!-4!) = 8!/4!*4! =8*7*6*5*/4*3*2*1* =70

A
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[#permalink]  03 Oct 2005, 19:06
we need the OA

originally , i calculated
8!/(8-4)! due to mention of the cards being arranged in ascending order.
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[#permalink]  03 Oct 2005, 19:07
UpperTaxBracket wrote:
we need the OA

originally , i calculated
8!/(8-4)! due to mention of the cards being arranged in ascending order.

Ooops... my bad... OA is A.
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[#permalink]  04 Oct 2005, 12:17
i think i'm missing something here, if arrangement/order is a part of this problem why is it considered a combination problem as opposed to a permutation one?
[#permalink] 04 Oct 2005, 12:17
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# PR '05 A teacher uses ten flash cards, numbered 1 through

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