Well I have never solved such a problem, But I will try to solve it. you mean to say originally there were x number of women and then 2 women were added. then while choosing groups of 3 women from (x + 2) women there are 56 selections available. so what is x ?

so equation should be (x + 2)!/ 3! (x+2 -3)! = 56

we can do some cancelling and find (x +2)(x + 1) x/ 3! =56

take 3! =6 on right hand side, we get

(x + 2)(x +1) x = 56 * 6

Now we can see x, (x +1) and (x + 2) are consecutive numbers and 56 = 7 * 8

so basically (x + 2)(x +1) x = 8 * 7 * 6

so x= 6

Well this is the only method I can come up with

let us wait for experts , they can give a better method than this and proper way of solving this question.