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# Price increased by M% from 1991 to 1992 and by N% from 1992

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Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
Followers: 1

Kudos [?]: 19 [0], given: 0

Price increased by M% from 1991 to 1992 and by N% from 1992 [#permalink]  02 Dec 2006, 07:20
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Price increased by M% from 1991 to 1992 and by N% from 1992 to 1993. What was the percentage increase in price from 1991 to 1993?

(1)MN = 300

(2) 100M + 100N + MN = 4,300
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Director
Affiliations: FRM Charter holder
Joined: 02 Dec 2006
Posts: 736
Schools: Stanford, Chicago Booth, Babson College
Followers: 8

Kudos [?]: 34 [0], given: 4

Re: DS: Percent Increases [#permalink]  02 Dec 2006, 07:30
Hermione wrote:
Price increased by M% from 1991 to 1992 and by N% from 1992 to 1993. What was the percentage increase in price from 1991 to 1993?

(1)MN = 300

(2) 100M + 100N + MN = 4,300

I think the answer is B.

As per statement 2, if we take M as either 10 or 30, and N as remaining number, then we can find the answer. We get unique values for M and N.
Director
Joined: 28 Dec 2005
Posts: 922
Followers: 2

Kudos [?]: 37 [0], given: 0

get B.

Let orig price be P
In 1992: Price = (1+m/100)P

In 1993 price = (1+m/100 + (1+m/100)*n/100)P

Thus knowing M/100+N/100+MN/10000 will help solve
Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
Followers: 1

Kudos [?]: 19 [0], given: 0

OA is B
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# Price increased by M% from 1991 to 1992 and by N% from 1992

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