Find all School-related info fast with the new School-Specific MBA Forum

It is currently 20 Oct 2014, 10:41

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Probab - Deck of cards

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Senior Manager
Senior Manager
User avatar
Joined: 24 Nov 2006
Posts: 351
Followers: 1

Kudos [?]: 11 [0], given: 0

Probab - Deck of cards [#permalink] New post 19 Jun 2007, 14:09
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
How many ways can one choose 6 cards from a normal deck of cards (13*4) in order to have all suits present?

A. (13^4) x 48 x 47
B. (13^4) x 27 x 47
C. 48C6
D. 13^4
E. (13^4) x 48C6
Director
Director
User avatar
Joined: 13 Mar 2007
Posts: 550
Schools: MIT Sloan
Followers: 4

Kudos [?]: 19 [0], given: 0

 [#permalink] New post 19 Jun 2007, 18:09
Hmm I am getting - 13^4 x 24 x 47

Four suits - 13c1 x 13c1 x 13c1 x 13c1

Remaining two cards - 48c2

=> 13^4 x 24 x 47 !
Manager
Manager
avatar
Joined: 28 Aug 2006
Posts: 160
Followers: 2

Kudos [?]: 12 [0], given: 0

 [#permalink] New post 19 Jun 2007, 19:32
I agree with grad_mba Should be 13^4 X24X 47
Senior Manager
Senior Manager
avatar
Joined: 04 Jun 2007
Posts: 349
Followers: 1

Kudos [?]: 14 [0], given: 0

Re: Probab - Deck of cards [#permalink] New post 19 Jun 2007, 22:47
[quote="Andr359"]How many ways can one choose 6 cards from a normal deck of cards (13*4) in order to have all suits present?

A. (13^4) x 48 x 47
B. (13^4) x 27 x 47
C. 48C6
D. 13^4
E. (13^4) x 48C6[/quote]

Agree with grad_mba and vijay2001.
The correct answer seems to be missing !!!

It should be (13C1)^4 * 48C2 = (13^4) * 24 * 47.
Senior Manager
Senior Manager
avatar
Joined: 21 Jun 2006
Posts: 289
Followers: 1

Kudos [?]: 18 [0], given: 0

 [#permalink] New post 20 Jun 2007, 12:42
A is the answer.. I guess if it is the probability of it happening just devided the number by 52C6 (no. of combinations)
Director
Director
User avatar
Joined: 13 Mar 2007
Posts: 550
Schools: MIT Sloan
Followers: 4

Kudos [?]: 19 [0], given: 0

 [#permalink] New post 20 Jun 2007, 19:28
i dont understand ..can someone explain ?

If it is veiwed as -

#ways for picking 1st card = 13

2nd - 13

3rd - 13

4th - 13

5th - 48

6th - 47

yes, choice A seems to work.

But what was wrong in my 1st approach ?!
Director
Director
avatar
Joined: 12 Jun 2006
Posts: 538
Followers: 1

Kudos [?]: 18 [0], given: 1

 [#permalink] New post 21 Jun 2007, 18:40
There are 52 cards in a deck and 13 cards in a suit.

imagine 6 slots:

Slot 1: 13 different cards for clubs

51 cards left to pick from - Slot 2: 13 different cards for hearts

50 cards left to pick from - Slot 3: 13 different cards for aces

49 cards left to pick from - Slot 4: 13 different cards for spades

***at this point we have 1 card from each suit, now there are no constraints and we can choose whatever cards we like***

Slot 5: 48 cards left to pick from

Slot 6: 47 cards left to pick from

13^4(48)47
Manager
Manager
avatar
Joined: 28 Aug 2006
Posts: 160
Followers: 2

Kudos [?]: 12 [0], given: 0

 [#permalink] New post 21 Jun 2007, 18:59
Ahh, Its is a permutation question(ways) not combinations. i guess answer is A
  [#permalink] 21 Jun 2007, 18:59
    Similar topics Author Replies Last post
Similar
Topics:
1 There are two decks of 10 cards each. The cards in each deck honchos 1 01 Dec 2013, 16:35
Experts publish their posts in the topic Deck of cards rxs0005 8 31 Aug 2010, 12:23
Experts publish their posts in the topic deck of 9 cards gmatcracker2010 1 17 Jun 2010, 05:20
Probability-Deck of cards Vijo 12 09 Mar 2005, 14:20
Probab- Cards swath20 3 14 Feb 2005, 11:49
Display posts from previous: Sort by

Probab - Deck of cards

  Question banks Downloads My Bookmarks Reviews Important topics  


cron

GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.