I am struggling with this question to solve (Source:its from a math book)
There are 3 black balls and 10 white balls.
if one is to pick 5 balls, What is the probability of picking 2 black and 3 white?
Answer I got:
Is there another approach?
Picking simultaneously is same as picking one after another.
So, let's see the probability of picking BBWWW.
But there are many other ways possible e.g. BWWWB, WWBBW etc
Number of all such arrangements = 5!/(2!*3!)
Required answer = (3/13)*(2/12)*(10/11)*(9/10)*(8/9)*5!/(2!*3!) = 40/143
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